The answer is C. <span>Light travels at different speeds in water and in glass.</span>
The force result in stretching the spring 10.0 centimeters is 2.5N.
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What is Hooke's law?</h3>
If a spring is stretched from its equilibrium position, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end.
F = kx
where k is the proportionality constant called the spring constant or force constant.
Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule.
Let the spring constant be very low 0.04N/m
The force applied is
F = 10 cm / 0.04
F = 0.1 m / 0.04
F = 2.5 N
Thus, the force result in stretching the spring 10cm is 2.5 N.
Learn more about hooke's law.
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The answer is b no problem
The current intensity is defined as the amount of charge flowing through a certain point of a wire divided by the time interval:
where Q is the charge and
is the time. Re-arranging the formula, we have
for the compressor in our problem, the intensity of current is I=66.1 A, while the time is
, so the amount of charge that crosses a certain point of the circuit during this time is
Answer: 1
Explanation: The highest eccentricity an ellipse can have is '1', a straight line.
