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Leokris [45]
3 years ago
12

Which experiment best shows water’s ability to act as a solvent? raise the temperature of water and record its boiling point. fr

eeze a flexible vessel of water and watch it expand. pour an ionic solid into water and see if it vanishes. place a leaf on top of the surface of water and see if it sinks?
Physics
2 answers:
IrinaVladis [17]3 years ago
8 0
The vanishing of an ionic solid (like table salt) would be an example of acting like a solvent
IceJOKER [234]3 years ago
4 0

Answer: pour an ionic solid into water and see if it vanishes.

Explanation: The solubility of substances is governed by: Like dissolves like, which states that polar compounds are soluble in polar solvents and non polar compounds are soluble in non polar solvents.

Ionic compounds are formed by combination of positively charged cations and negatively charged anions which are held by strong coloumbic forces.When ionic compounds are dissolved in water, the ions are dissociated due to high dielectric constant of water and thus dissolve in water.

Water being a polar solvent is able to dissolve ionic or polar compounds in it.

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IgorC [24]

Known :

l = 7 cm

w = 4 cm

Asked :

h = ...?

Answer :

V = B triangle × h (long)

35 = ½ × 4 × h × 7

35 = ½ × 28 × h

35 = 14 h

h = 35 ÷ 14

h = 2,5 cm

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3 years ago
What can cause an increase in density that results in a deep ocean current
mrs_skeptik [129]
The movement of plates
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3 years ago
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Convert 5.5 kilometers into millimeters.​
dimaraw [331]

Answer:

5500000 millimeters

Explanation:

1 kilometre= 1000 meter

5.5 km=5.5 * 1000

=5500

Now,

1 metre = 1000 millimetres

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4 0
2 years ago
One wire carries a current of I1= 2 Amps, and the other carries a parallel current (same direction, wires are side by side) of I
Yuki888 [10]

Answer:F=3\times 10^{-5} N

Explanation:

Given

I_1=2 Amps

I_2=0.75 Amps

Length of each wires\left ( L\right )=5 m

Distance between wires \left ( r\right )=5 cm

Force per unit length =\frac{\mu_0I_1I_2}{2\pi r}

F'=\frac{2\times 10^{-7}\times 2\times 0.75}{2\pi \times 0.05}

F'=6\times 10^{-6}

Force for L=5 m

F=3\times 10^{-5} N

6 0
3 years ago
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