Answer:
Force, ![F=2.27\times 10^4\ N](https://tex.z-dn.net/?f=F%3D2.27%5Ctimes%2010%5E4%5C%20N)
Explanation:
Given that,
Mass of the bullet, m = 4.79 g = 0.00479 kg
Initial speed of the bullet, u = 642.3 m/s
Distance, d = 4.35 cm = 0.0435 m
To find,
The magnitude of force required to stop the bullet.
Solution,
The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :
![F.d=\dfrac{1}{2}m(v^2-u^2)](https://tex.z-dn.net/?f=F.d%3D%5Cdfrac%7B1%7D%7B2%7Dm%28v%5E2-u%5E2%29)
Finally, it stops, v = 0
![F.d=-\dfrac{1}{2}m(u^2)](https://tex.z-dn.net/?f=F.d%3D-%5Cdfrac%7B1%7D%7B2%7Dm%28u%5E2%29)
![F=\dfrac{-mu^2}{2d}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B-mu%5E2%7D%7B2d%7D)
![F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B-0.00479%5Ctimes%20%28642.3%29%5E2%7D%7B2%5Ctimes%200.0435%7D)
F = -22713.92 N
![F=2.27\times 10^4\ N](https://tex.z-dn.net/?f=F%3D2.27%5Ctimes%2010%5E4%5C%20N)
So, the magnitude of the force that stops the bullet is ![2.27\times 10^4\ N](https://tex.z-dn.net/?f=2.27%5Ctimes%2010%5E4%5C%20N)
Answer:
June Mar Fajardo
plus he plays for Phillipines men's national basketball team
and baseball is my favorite team sport because everyone has a role no matter how big or small it is
Answer: 9m
Explanation:
Our given:
Acceleration- 5m/s^2
Time- 3.6 seconds
Use the equation d = 1/2 • a • t^2
d = 1/2 • 5m/s^2 • 3.6 secs
d = 2.5m/s^2 • 3.6 secs
d = 9m
I hope this is correct
Answer:
often Positive and negative charges balance each other which gives an overall neutral charge. if they are unbalanced then it will result in static electricity.