3 years ago

Need help on this quickly

Physics

1 answer:

IrinaVladis [17]3 years ago

3 0

Answer:

Pretty sure its the last answer for model A

Explanation:

Negative a Positive go together and two negatives cant stick

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A person pushes a 50kg box to the right with 100N of force at a constant velocity of 5m/s. Calculate the coefficient of friction

Anna11 [10]

The weight of the box is 50x9.8 = 490 N. The force of friction is 100N. F= μΝ so coefficient = 100/490 = 0.20

8 0

2 years ago

The moon is 3.85 x 10 to the 8 m from earth and has a diameter of 3.48 x 10 to the 6 m. You have a pea (diameter = 0.50 cm) and

polet [3.4K]

Answer:

(a) dime

Explanation:

Convert all to metric unit:

0.5 cm = 0.005 m

1.8 cm = 0.018 m

71 cm = 0.71 m

In order to find out we would need to calculate the ratio R between the object diameter d and their distance s to our eyes:

$R_m = \frac{d_m}{s_m} = \frac{3.48*10^6}{3.85*10^8} \approx 0.009$

$R_p = \frac{d_p}{s_p} = \frac{0.005}{0.71} \approx 0.007$

$R_d = \frac{d_d}{s_d} = \frac{0.018}{0.71} \approx 0.0253$

Since the ratio of the dime is larger than the ratio of the moon, and the ratio of the pea is smaller than the ratio of the moon, only the (a) dime can cover your view of the moon.

3 0

3 years ago

Shante makes a diagram to compare the effects of short-term and long-term environmental changes. Which statement should she plac

irinina [24]

Answer: affect organisms
hope this helps you out .

5 0

2 years ago

Can someone help me with this

yKpoI14uk [10]

bonded pairs of electrons, lone pairs of electrons.

4 0

3 years ago

What potential difference is needed to give a helium nucleus (q=2e) 85.0 kev of kinetic energy?

Vilka [71]

The kinetic energy K given to the helium nucleus is equal to its potential energy, which is
$E=q \Delta V$
where q=2e is the charge of the helium nucleus, and $\Delta V$ is the potential difference applied to it.
Since we know the kinetic energy, we have
$E=K=85~keV=q \Delta V$
and from this we can find the potential difference:
$\Delta V = \frac{K}{q}= \frac{85~keV}{2e}=42.5~kV$

6 0

2 years ago