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4 years ago

Describe the relationship between motion and a reference point.

Physics

2 answers:

Stells [14]4 years ago

8 0

Answer:

A <u>object </u>is in motion when its distance from another object it changing.

a <u>reference </u>point is a place or object used for comparison to determine if something is in motion. You can assume that the refrence point is stuck or not moving.

steposvetlana [31]4 years ago

4 0

Answer:

An object is in motion when its distance from another object is changing. ... A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving.

Explanation:

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A cosmic ray electron moves at 7.45 â 106 m/s perpendicular to the earth's magnetic field at an altitude where field strength is

kupik [55]

The magnetic force on the electron is:
$F=qvB \sin \theta$
where q is the electron charge, v the electron speed, B the magnetic field intensity and $\theta$ is the angle between v and B. Since the electron is traveling perpendicular to the magnetic field, $\sin \theta = \sin 90^{\circ}=1$ , so we can write
$F=qvB$

This force acts as centripetal force of the motion, $F_c = m \frac{v^2}{r}$ , where m is the electron mass and r the radius of the circular orbit. So we can write:
$qvB=m \frac{v^2}{r}$
and by re-arranging this equation, we find the radius of the circular orbit, r:
$r= \frac{mv}{qB}= \frac{(9.1 \cdot 10^{-31}kg)(7.45 \cdot 10^6 m/s)}{(1.6 \cdot 10^{-19}C)(1.10 \cdot 10^{-5}T)}= 3.85 m$

6 0

3 years ago

(b) Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a c

andreyandreev [35.5K]

Answer:

$\frac{dA}{dt} \approx 245.044\,\frac{m^{2}}{s}$

Explanation:

The formula for the surface of the circle is:

$A(r) = \pi\cdot r^{2}$

The rate of change of the spill area is obtained by deriving the previous formula in terms of time:

$\frac{dA}{dt} = 2\pi\cdot r\cdot \frac{dr}{dt}$

Finally, variables are replaced by known data:

$\frac{dA}{dt} = 2\pi\cdot (39\,m)\cdot (1\,\frac{m}{s} )$

$\frac{dA}{dt} \approx 245.044\,\frac{m^{2}}{s}$

4 0

4 years ago

Read 2 more answers

A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occ

Neporo4naja [7]

Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
$F=ma$
Using $m=65 kg$ and $a=5 m/s^2$ , we can find the value of the force applied to the roller-blade to obtain this acceleration:
$F=(65 kg)(5 m/s^2)=325 N$

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3 years ago

This is a computer program, why is there an error between the computer values and the nominal values of R?

ss7ja [257]

Answer:

the difference is due to resistance tolerance

Explanation:

In mathematical calculations, either done by hand or in a computer program, the heat taken from the resistors is the nominal value, which is the writing in its color code, so all calculations give a result, but the Resistors have a tolerance, indicated by the last band that is generally 5%, 10%, 20% and in the expensive precision resistance can reach 1%.

This tolerance or fluctuation in the resistance value is what gives rise to the difference between the computation values and the values measured with the instruments, multimeters.

Another source of error also occurs due to temperature changes in the circuit that affect the nominal resistance value, there is a very high resistance group that indicates the variation with the temperature, they are only used in critical circuits, due to their high cost

In summary, the difference is due to resistance tolerance.

5 0

4 years ago

Batteries are rated in terms of ampere-hours (A·h). For example, a battery that can produce a current of 2.00 A for 3.00 h is ra

Reptile [31]

(a) 423 J

The power of the battery is the ratio between the total energy stored (E) and the time elapsed (t):

$P=\frac{E}{t}$