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3 years ago

Help me asap plz !!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

frez [133]3 years ago

6 0

Answer:

The answer will be A. 27f

Novosadov [1.4K]3 years ago

4 0

Answer:

dont hold me to it but im pretty sure the anwser is -3

Step-by-step explanation:

-15+12=-3

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If f (x)=8-5x, find the value of f(2-k)

Helen [10]

Hello from MrBillDoesMath!

Answer:

f(2-k) = -2 + 5k

Discussion:

If f(x) = 8 - 5x , then

f(2-k) = 8 - 5(2-k) =>

f(2-k) = 8 - 10 + 5k =>

f(2-k) = -2 + 5k

Regards,

MrB

6 0

3 years ago

write the equation of a line in slope intercept form that is perpendicular to the line y = 3/5 x - 1 and passes through the poin

Simora [160]

Can you write complete question

4 0

3 years ago

What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

7 0

3 years ago

b is the midpoint of AC and E is the midpoint of BD if A(-9,-4) C(-1,6) and E(-4,-3) find the coirdinates of D

natima [27]

To find the coordinate of the point D, we can use the Midpoint point of a line Segment formula. Calculation of the formula are as follows,

Given two points A(x1,y1) and C(x2,y2), we need to locate the midpoint coordinate of this line denoted as B(x,y).

To solve for the value of x and y, we get,

x=(x1+x2)/2 and y=(y1+y2)/2

For the given problem, we need to solve first the midpoint coordinate of AC which is B.

So, A(-9,-4)=A(x1,y1) and C(-1,6)=C(x2,y2)

Hence,

B(x,y)=B((-9+(-1))/2, (-4+6)/2)=B(-10/2,2/2)=B(-5,1)

Now, since the midpoint is given but one point in the line is missing. To solve for the missing point D(x2,y2), we need to use the Midpoint Segment Formula.

That is, B(-5,1)=B(x,y) and E(-4,-3)=E(x1,y1)

So,

x=(x1+x2)/2 and y=(y1+y2)/2

-5=(-4+x2)/2 and 1=(-3+y2)/2

By Cross Multiplication and Transposing method,

-5(2)=-4+x2 and 1(2)=-3+y2

x2=-10+4=-6 and y2=3+2=5

Thus, the coordinate of D is D(-6,5).

5 0

3 years ago

What is the 308th term of the sequence 11,12.5,14,15.5,17...

Alecsey [184]

$\huge\boxed{471.5}$

The formula for an arithmetic sequence is as follows:

$a_n=a_1+(n-1)d$

In this formula, $a_n$ represents the $n$ th term of the sequence and $d$ represents the common difference between each term.

Plug in the known values.

$a_{308}=11+(308-1)1.5$

Subtract.

$a_{308}=11+307*1.5$

Multiply.

$a_{308}=11+460.5$

Add.

$a_{308}=\boxed{471.5}$

6 0

2 years ago