Answer:
i). Compression ratio = 3.678
ii). fuel consumption = 0.4947 kg/hr
Explanation:
Given :

Fuel calorific value = 45 MJ/kg
We know, engine efficiency is given by,

where
is compression ratio = 
= 
where
is compression volume
is swept volume
Now it is given that swept volume at 30% of compression, 70% of the swept volume remains.
Then, 
and at 70% compression, 30% of the swept volume remains
∴
We know,








∴ 
Therefore, compression ratio is
= 3.678
Now efficiency, 

, this is the ideal efficiency
Therefore actual efficiency, 


Therefore total power required = 1 kW x 3600 J
= 3600 kJ
∴ we know efficiency, 



Therefore fuel required = 
= 0.4947 kg/hr