Answer:
The total hole mobility is 41.67 cm²/V s
Explanation:
Data given by the exercise:
hole mobility due to lattice scattering = ul = 50 cm²/V s
hole mobility due to ionized impurity = ui = 250 cm²/V s
The total mobility is equal:
Answer:Vb=-6i-(-0.1ωab+8)j m/s
Explanation:
Va=V0+Va0
Va=V0+(ra0 x ωao)
ω=Angular velocity of link A0
Using r0a=0.1m;
Va=V0+(0.1i x ω0a K)
Va=0
ixk=j
Va=0+0.1ω0aj
Calculating te velocity of using te equation below
Vb=Va+Vba
Vb=Va+ωab x rba
ωab=40rad/s
rab=-0.21i+0.15j
Va=0.1ω0aj
Vb=Va+ωabxrba
Vb=0.1ω0aj+40k x -(0.21i+0.15j)
Vb=0.1ω0aj-8j-6i
Vb=-6i-(-0.1ωab+8)j m/s
Answer:
Steps:
1. Create a text file that contains blade diameter (in feet), wind velocity (in mph) and the approximate electricity generated for the year
2. load the data file for example, in matlab, use ('fileame.txt') to load the file
3. create variables from each column of your data
for example, in matlab,
x=t{1}
y=t{2}
4. plot the wind velocity and electricity generated.
plot(x, y)
5. Label the individual axis and name the graph title.
title('Graph of wind velocity vs approximate electricity generated for the year')
xlabel('wind velocity')
ylabel('approximate electricity generated for the year')
Answer:
Inspectors use inductive reasoning on the job.
Explanation:
I just took the test.
