Answer:
It will create a massive drag and pretty much stop the motor.
Explanation:
Answer:
![0.845\ \text{N}](https://tex.z-dn.net/?f=0.845%5C%20%5Ctext%7BN%7D)
Explanation:
g = Acceleration due to gravity at sea level = ![9.81\ \text{m/s}^2](https://tex.z-dn.net/?f=9.81%5C%20%5Ctext%7Bm%2Fs%7D%5E2)
R = Radius of Earth = 6371000 m
h = Altitude of observatory = 4205 m
Change in acceleration due to gravity due to change in altitude is given by
![g_h=g(1+\dfrac{h}{R})^{-2}\\\Rightarrow g_h=9.81\times(1+\dfrac{4205}{6371000})^{-2}\\\Rightarrow g_h=9.797\ \text{m/s}^2](https://tex.z-dn.net/?f=g_h%3Dg%281%2B%5Cdfrac%7Bh%7D%7BR%7D%29%5E%7B-2%7D%5C%5C%5CRightarrow%20g_h%3D9.81%5Ctimes%281%2B%5Cdfrac%7B4205%7D%7B6371000%7D%29%5E%7B-2%7D%5C%5C%5CRightarrow%20g_h%3D9.797%5C%20%5Ctext%7Bm%2Fs%7D%5E2)
Weight at sea level
![W=mg\\\Rightarrow W=65\times 9.81\\\Rightarrow W=637.65\ \text{N}](https://tex.z-dn.net/?f=W%3Dmg%5C%5C%5CRightarrow%20W%3D65%5Ctimes%209.81%5C%5C%5CRightarrow%20W%3D637.65%5C%20%5Ctext%7BN%7D)
Weight at the given height
![W_h=mg_h\\\Rightarrow W_h=65\times 9.797\\\Rightarrow W_h=636.805\ \text{N}](https://tex.z-dn.net/?f=W_h%3Dmg_h%5C%5C%5CRightarrow%20W_h%3D65%5Ctimes%209.797%5C%5C%5CRightarrow%20W_h%3D636.805%5C%20%5Ctext%7BN%7D)
Change in weight ![W_h-W=636.805-637.65=-0.845\ \text{N}](https://tex.z-dn.net/?f=W_h-W%3D636.805-637.65%3D-0.845%5C%20%5Ctext%7BN%7D)
Her weight reduces by
.
Answer:
Attached is the complete question but the weight of the mailbox and cross bar differs from the given values which are : weight of mail box = 3.2 Ib, weight of the uniform cross member = 10.3 Ib
Answer : moment of inertia = 186.7 Ib - in
Explanation:
Given data
weight of the mailbox = 3.2 Ib
weight of the uniform cross member = 10.3 Ib
The origin is of mailbox and cross member is 0
The perpendicular distance from Y axis of centroid of the mailbox
= 4 + (25/2) = 16.5"
The centroid of the bar =( ( 1 + 25 + 4 + 4 ) / 2 ) - 4 = 13"
therefore The moment of Inertia( Mo) = (3.2 * 16.5) + ( 10.3 * 13)
= 52.8 + 133.9 = 186.7 Ib-in
Answer:
The part of the system that is considered the resistance force is;
B
Explanation:
The simple machine is a system of pulley that has two pulleys
The effort, which is the input force at A gives the value of the tension at C and D which are used to lift the load B
Therefore, we have;
A = C = D
B = C + D = C + C = 2·C
∴ C = B/2
We have;
C = B/2 = A
Therefore, with the pulley only a force, A equivalent to half the weight, B, of the load is required to lift the load, B
The resistance force is the constant force in the system that that requires an input force to overcome in order for work to be done
It is the force acting to oppose the sum of the other forces system, such as a force acting in opposition to an input force
Therefore, the resistance force is the load force, B, for which the input force, A, is required in order for the load to be lifted.