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o-na [289]
3 years ago
11

Convert 435.5 lbs to kilograms

Physics
1 answer:
sergey [27]3 years ago
8 0
Final Answer is - 197.53948
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A copper rod 81 cm long is used to poke a fire. the hot end of the rod is maintained at 105° c and the cool end has a constant t
Ugo [173]
The temperature inside the copper rod varies linearly with the distance from the hot end of the rod. This means that we can find the temperature at 23 cm (let's call it 'point A') from the cool end by solving a linear proportion.

The temperature difference between the two ends of the rod is
\Delta T = 105^{\circ}-21^{\circ} = 84^{\circ}
and this corresponds to a length of 81 cm. Therefore, we can write:
84^{\circ}:81~cm = x:23~cm
from which we find
x=23.8~^{\circ}
This is not the final answer actually; this is the temperature difference between the cool end and point A. So, the temperature at point A is
T_A = 21^{\circ}+x=44.8^{\circ}
7 0
3 years ago
How can we realize that light travel in straight line ?​
Norma-Jean [14]

Answer:

It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.

Explanation:

The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.

One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light

Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.  

3 0
3 years ago
A runner runs 2.0 km in 5.0 minutes
Nadya [2.5K]

Answer: What is this supposed to be converted into?

Explanation:

4 0
3 years ago
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An airplane is .68 Kilometers long. How many Millimeters long is the plane?
xxTIMURxx [149]

Answer:

680000

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4 0
2 years ago
Read 2 more answers
Suppose you observe two stars and you know they have the same luminosity. If one star is twice as far away as the other, the mor
rosijanka [135]

Answer:

The farther star will appear 4 times fainter than the star that is near to the observer.

Explanation:

Since it is given that the luminosity of the 2 stars is same thus they radiate the same energy per unit time

Consider a spherical wave front of energy 'E' that leaves both the stars (Both radiate 'E' as they have same luminosity)

This Energy is spread over the whole surface area of sphere Thus when the wave front is at a distance 'r' the energy per unit surface area is given by

e_{1}=\frac{E}{4\pi r^{2}}

For the star that is twice away from the earth the distance is '2r' thus we will receive an energy given by

e_{2}=\frac{E}{4\pi (2r)^{2}}=\frac{E}{8\pi r^{2}}=\frac{e_{1}}{4}

Hence we sense it as 4 times fainter than the nearer star.

5 0
3 years ago
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