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oksano4ka [1.4K]
3 years ago
12

Can you help me on this? it is a phyisical science question.

Physics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

Electron

Explanation:

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A car starts from rest and experiences a constant acceleration of 5 m/s2 until it reaches a speed of 650 meters
Zigmanuir [339]

Answer: Time.

Explanation:

Hey there!!!

The reason is,

According to the question we have,

Initial velocity = 0m/s { as it starts from rest}.

Final velocity = 650 m/s

acceleration = 5m/s^2.

Looking on this formula,

a =  \frac{v - u}{t}

Where "v" represents final velocity, "u" represents initial velocity and "a" represents acceleration. We dont have is time "t".

So, it's obvious that tine is an unknown variable.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
3 years ago
A hoop and a solid disc are relased from rest
Murljashka [212]

Answer:

1) The hoop and a solid disc rolling without slipping down an incline plane.

Their final velocities are proportional to their moment of inertia.

The condition for moment of inertia: v = ωR

We will use conservation of energy.

<u>For the hoop:</u>

K_1 + U_1 = K_2 + U_2\\0 + m_hgh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}I\omega_h^2 + 0

They are released from rest, so their initial kinetic energy is zero. And when they reach the bottom, their final potential energy is also zero.

The moment of inertia of a hoop is

I_h = m_hR^2

Let's continue with the energy equations:

m_h gh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}(m_hR^2)(\frac{v_h^2}{R^2})\\m_hgh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}m_hv_h^2\\m_hgh = m_hv_h^2\\v_h = \sqrt{gh}

Similarly <u>for the solid disk</u> with a moment of inertia of (1/2)mR^2:

K_1 + U_1 = K_2 + U_2\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{2}I_d\omega_d^2\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{2}(\frac{1}{2}m_dR^2)(\frac{v_d^2}{R^2})\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{4}m_dv_d^2\\m_dgh = \frac{3}{4}m_dv_d^2\\v_d = \sqrt{\frac{4gh}{3}}

Comparing the final velocities, we can conclude that the solid disk reaches the bottom first.

2) The angular acceleration of the pebble is equal to the angular acceleration of the tire, since they stuck together. We can deduce the angular acceleration of the tire from the linear acceleration of the bicycle.

The kinematics equations states that

v = v_0 + at\\4.47 = 0 + 2a\\a = 2.235 ~m/s^2

where a is the linear acceleration.

The relation with the angular and linear acceleration is

a = \alpha R

where R is the radius of the tire. Since it is not given in the question, we will leave it as R.

The angular acceleration of the small pebble is

\alpha = 2.235/R ~m/s^2

4 0
4 years ago
Read 2 more answers
PLEASE HELP! A river current has a velocity of 5km/h relative to the shore, and a boat moves in the same direction as the curren
Usimov [2.4K]

add the river's velocity to the boat's velocity

5+ 5 = 10 km/h

Hope this helps!

5 0
4 years ago
What is the wavelength of an earthquake wave if it has a speed of 4 km/s and a frequency of 7 Hz?
damaskus [11]

Answer: 0.571 km/s

λ = v/f

λ = 4/7

λ = 0.571 km/s


7 0
4 years ago
What are some similarities and differences between elements, compounds, and mixtures?
Lina20 [59]
T<span>he </span>similarities between compounds<span> and </span>mixtures<span> are that they are both made up of two or more </span>elements<span> and that they could both be separated and then mixed with different </span>elements<span> to make a new </span>mixture<span> and </span>compound<span>.

</span>
4 0
3 years ago
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