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Degger [83]
2 years ago
15

What’s the difference between the offspring of an asexual organism and a sexual organism

Physics
2 answers:
laiz [17]2 years ago
4 0
The offspring of an asexual organism (since asexual reproduction only requires one parent) will be completely identical to the parent, like bacteria or fungi. The offspring of a sexual organism (since sexual reproduction requires two organisms) will be a combination of both parents, like animals or (some) flowers.
Sever21 [200]2 years ago
3 0
The asexual organisms will be the exact copy of the parents and the sexual organisms with have variety
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Which element of variation would not be affected by adding the data value 15 to the data set {3, 5, 6, 8, 9, 10, 13, 14}?
Anna11 [10]
The answer to this would be 15
4 0
3 years ago
Waves : Transfer of Energy
garri49 [273]

✒ Answer

In the case of still lake and ocean water how are they different in transferring energy from one location to another?

  • Answer:Energy is transferred in waves through the vibration of particles

In what direction will you move a rope to create transverse waves?

  • Answer: in the direction of the black arrow

In what direction will you move a slinky to create longitudinal waves?

  • Answer: parallel to the direction that energy is transported.

7 0
2 years ago
Radiation from the Sun The intensity of the radiation from the Sun measured on Earth is 1360 W/m2 and frequency is f = 60 MHz. T
Zina [86]

a) Total power output: 3.845\cdot 10^{26} W

b) The relative percentage change of power output is 1.67%

c) The intensity of the radiation on Mars is 540 W/m^2

Explanation:

a)

The intensity of electromagnetic radiation is given by

I=\frac{P}{A}

where

P is the power output

A is the surface area considered

In this problem, we have

I=1360 W/m^2 is the intensity of the solar radiation at the Earth

The area to be considered is area of a sphere of radius

r=1.5\cdot 10^{11} m (distance Earth-Sun)

Therefore

A=4\pi r^2 = 4 \pi (1.5\cdot 10^{11})^2=2.8\cdot 10^{23}m^2

And now, using the first equation, we can find the total power output of the Sun:

P=IA=(1360)(2.8\cdot 10^{23})=3.845\cdot 10^{26} W

b)

The energy of the solar radiation is directly proportional to its frequency, given the relationship

E=hf

where E is the energy, h is the Planck's constant, f is the frequency.

Also, the power output of the Sun is directly proportional to the energy,

P=\frac{E}{t}

where t is the time.

This means that the power output is proportional to the frequency:

P\propto f

Here the frequency increases by 1 MHz: the original frequency was

f_0 = 60 MHz

so the relative percentage change in frequency is

\frac{\Delta f}{f_0}\cdot 100 = \frac{1}{60}\cdot 100 =1.67\%

And therefore, the power also increases by 1.67 %.

c)

In this second  case, we have to calculate the new power output of the Sun:

P' = P + \frac{1.67}{100}P =1.167P=1.0167(3.845\cdot 10^{26})=3.910\cdot 10^{26} W

Now we want to calculate the intensity of the radiation measured on Mars. Mars is 60% farther from the Sun than the Earth, so its distance from the Sun is

r'=(1+0.60)r=1.60r=1.60(1.5\cdot 10^{11})=2.4\cdot 10^{11}m

Now we can find the radiation intensity with the equation

I=\frac{P}{A}

Where the area is

A=4\pi r'^2 = 4\pi(2.4\cdot 10^{11})^2=7.24\cdot 10^{23} m^2

And substituting,

I=\frac{3.910\cdot 10^{26}}{7.24\cdot 10^{23}}=540 W/m^2

Learn more about electromagnetic radiation:

brainly.com/question/9184100

brainly.com/question/12450147

#LearnwithBrainly

4 0
2 years ago
What mineral is most abundant in granite
77julia77 [94]
I believe it would be orthoclase feldspar, quartz, micas, and amphiboles are the most abundant in granite.<span />
3 0
3 years ago
Suppose that the acceleration of a model rocket is proportional to the difference between 160 ft/sec and the rocket's velocity.
Levart [38]

Answer:

Explanation:

Given ,

dv / dt = k ( 160 - v )

dv / ( 160 - v ) = kdt

ln ( 160 - v ) = kt + c , where c is a constant

when t = 0 , v = 0

Putting the values , we have

c = ln 160

ln ( 160 - v ) = kt + ln 160

ln ( 160 - v / 160 ) = kt

(160 - v ) / 160 = e^{kt}

1 - v / 160 = e^{kt }

v / 160 = 1 - e^{kt }

v = 160 ( 1 - e^{kt } )

differentiating ,

dv / dt = - 160k e^{kt }

acceleration a   = - 160k e^{kt }

given when t = 0 , a = 280

280 = - 160 k

k = - 175

a = - 160 x - 175 e^{kt}

a = 28000 e^{kt}

when a = 128  t = ?

128 = 28000 e^{kt}

e^{kt } = .00457

5 0
2 years ago
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