There are 19.5 g Na in 71.4 g NaHCO₃
Calculate the <em>molecular mass of NaHCO₃</em>.
1 Na = 1 × 22.99 u = 22.99 u
1 H = 1 × 1.008 u = 1.008 u
1 C = 1 × 12.01 u = 12.01 u
3 O = 3 × 16.00 u = <u>48.00 u
</u>
TOTAL = 84.008 u
So, there are 22.99 g of Na in 84.008 g NaHCO₃.
∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na
Answer:
109° 27'
Explanation:
The ammonium ion is tetrahedral in shape, all the HNH bonds are exactly at the tetrahedral bond angle since there are only bond pairs in the structure and no lone pairs. Recall that lone pairs decrease the bond angke from the ideal value in a tetrahedron due to higher repulsion.
A nuclear reaction in which a heavy nuclear splits spontaneously or on impact with another particle with the release of energy- fission
A nuclear reaction in which atomic nucleus with the release of energy-fusion
The energy harnessed in nuclei is released in nuclear reaction. Fission is the splitting of a heavy nucleus into lighter nuclei and fusion is the combining of nuclei to form a bigger and heavier nucleus
Answer:
The correct option is: Br₂--------->2 Br(g)
Explanation:
Bond dissociation is a process in which energy is applied to break a chemical bond between the atoms of a molecule to give free atoms.
In the given reaction: Br₂-------->2 Br(g)
The covalent bond in Br₂ molecule dissociates to give two moles of bromine atoms. Therefore, it is a bond dissociation reaction.
Molar mass RbMnO₄ = 204.40 g/mol
1 mole ---------- 204.40 g
7.88 mole ------ ?
mass = 7.88 * 204.40 / 1
mass = 1610.672 g
hope this helps!
