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andrew11 [14]
3 years ago
5

Which type of galaxy can be commonly shaped by collisions or the gravitational pull of other galaxies?

Physics
1 answer:
STatiana [176]3 years ago
3 0
<span>Milky Way Galaxy, LMC SMC

WhirlPool Galaxy

</span>
You might be interested in
A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh
Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(c) 9.446 rad/sec^2

(d) 396.22 revolution

Explanation:

We have given that diameter d = 1.63 m

So radius r=\frac{d}{2}=\frac{1.63}{2}=0.815m

Angular speed N = 79.9 rev/min

(a) We know that angular speed in radian per sec

\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 79.9}{60}=8.362rad/sec

(b) We know that linear speed is given by

v=r\omega =0.815\times 8.362=6.815m/sec

(c) We have given final angular velocity \omega _f=675rev/min

And \omega _i=79.9rev/min

Time t = 63 sec

Angular acceleration is given by \alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2

(d) Change in angle is given by

\Theta =\frac{1}{2}(\omega _i+\omega _f)t=\frac{1}{2}(675+79.9)\times 1.05=396.22rev

7 0
3 years ago
A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2 m/s to 4 m/s?
mash [69]

Answer:

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

Explanation:

The momentum of an object is given by the product between its mass (m) and its velocity (v):

p=mv

Let's apply this formula to calculate the initial momentum and final momentum of the ball:

- initial momentum:

p_i = m v_i = (6 kg)(2 m/s)=12 kg m/s

- Final momentum:

p_f = m v_f = (6 kg)(4 m/s)=24 kg m/s

So, the correct answer is

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

3 0
3 years ago
Read 2 more answers
Write a difference between force and work? ​
Nesterboy [21]

Answer:

force is a derived quantity

work is a fundamental quantity

2.Force is measured in Newton why work is measured in Newton per seconds (N/s)

Explanation:

no

3 0
3 years ago
Read 2 more answers
A motorist drives north for 35.0 minutes at 85.0 kph. He then stops for 15.0 minutes. The motorist then drives 130.0 km in 2.0 h
o-na [289]

Answer:

A. 216.36 \frac{km}{h}

B. 96.56 \frac{km}{h}

Explanation:

Let s_{1} be the distance in first part.

s_{1} = velocity × time

s_{1} = 85 × \frac{35}{60}

s_{1} = 49.58 km

Let s_{2} be the distance in first part.

s_{2} = 130 km

Average velocity = \frac{Total displacement}{Total time}

When second leg of the trip is

A. Toward north

Average velocity = \frac{[tex] s_{1} + s_{2}}{Total time}  [/tex]

Average velocity = \frac{130+49.58}{0.25+0.58}

Average velocity =216.36 \frac{km}{h}

B. Toward south

Average velocity = \frac{[tex] s_{1} - s_{2}}{Total time}  [/tex]

Average velocity = \frac{130-49.58}{0.25+0.58}

Average velocity =96.56 \frac{km}{h}


3 0
3 years ago
Unless an object at rest is acted upon by a force, it stays at rest due to its
Lelu [443]
There are a lot of things about this whole statement that bother me,
but I'm pretty sure you're not interested in those.  You just want a word
to glue onto the end and complete the statement.  OK.  Use "inertia".
4 0
3 years ago
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