Explanation:
For Mg, (1.2 g Mg/24 g Mg) = 0.05 mol Mg.
For Cl, (3.55 g Cl/35.5 g Cl) = 0.1 mol Cl
So the ratio now is
Mg:Cl = 0.05 : 0.1 = 1:2
I got the 1:2 ratio by dividing both by the smallest number, which is 0.05 mol. Therefore, the empirical for formula of the substance is
Answer:
5.20 grams of Br₂
Explanation:
From our previous knowledge;
We understand that:
The number of moles of a given element = mass of the element divided by its molar mass.
Mathematically:
From the given information, let's assume that the 0.065 moles of liquid -bromine partake in the reaction.
From the periodic table, the molar mass of Bromine is = 79.9 g/mol
As such, the mass of liquid that partakes is calculated as:
0.065 mol = mass/ 79.9 g/mol
mass = 0.065 mol × 79.9 g/mol
mass of liquid that partakes in the reaction = 5.20 grams of Br₂
Answer:
45.2 mL must be meausred for the experiment
Explanation:
The density of the acetic acid is 1.105 g/mL, so this data gives the information about how many grams are contained in 1mL of volume.
Notice that 1 mL = 1 cm³
Acetic acid Density = Acetic acid mass / acetic acid volume
1.105 g/mL = 50 g / acetic acid volume
Acetic acid volume = 50 g / 1.105g/mL ⇒ 42.5 mL
Answer:
The red dot represents the melting point of the element, which as stated is approximately 19.9 degrees Celsius and how long it took for the heat to properly completely dissolve it.
The question kind of answers itself however, is there a way to re-word it or is there a different answer you're looking for?