What size container do you need to hold 0.0459 mol of N2 gas at stp

Chemistry

1 answer:

insens350 [35]4 years ago

3 0

Answer:

The size of the container needed is 1,03 liters

Explanation:

We use the formula PV=nRT. The STP conditions correspond to 1 atm of pressure and 273 K of temperature.

PV=nRT V=(nRT)/P

V= (0,0459 mol x 0,082 l atm/ K mol x 273K)/1 atm= 1,0275174 liters

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