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s344n2d4d5 [400]

3 years ago

7

Using methods to determine something's actual age is known as what? Carbon 14 dating Uranium 235 dating Relative dating Absolute

dating

2 answers:

Travka [436]3 years ago

8 0

Your answer would be D.

Nesterboy [21]3 years ago

5 0

The answer will be carbon 14 dating hoped it helped. :))

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Will reward brainliest

Kazeer [188]

<span>Stratosphere. ...Mesosphere. ...Thermosphere. ...Ionosphere. ...<span>Exosphere.</span></span>

6 0

3 years ago

Read 2 more answers

Consider three gases: Ar, SF6, and Cl2. If 50.0 grams of these gases are placed in each of three identical containers, which con

adoni [48]

The ideal gas law:
$pV=nRT \Rightarrow p=\frac{nRT}{V}$
p - pressure, n - number of moles, R - the gas constant, T - temperature, V - volume

The volume and temperature of all three containers are the same, so the pressure depends on the number of moles. The greater the number of moles, the higher the pressure.
The mass of gases is 50 g.

$Ar \\
M \approx 39.948 \ \frac{g}{mol} \\
n=\frac{50 \ g}{39.948 \ \frac{g}{mol}} \approx 1.25 \ mol \\ \\
SF_6 \\
M \approx 146.06 \ \frac{g}{mol} \\
n=\frac{50 \ g}{146.06 \ \frac{g}{mol}} \approx 0.34 \ mol \\ \\
Cl_2 \\
M=70.9 \ \frac{g}{mol} \\
n=\frac{50 \ g}{70.9 \ \frac{g}{mol}} \approx 0.71 \ mol$

The greatest number of moles is in the container with Ar, so there is the highest pressure.

4 0

3 years ago

Why does the concentration of a product increase as the amount of the reactant decreases? (More 10+ pt questions on profile)

skad [1K]

As reactant concentration decreases, the forward. reaction slows. As product concentration increases, the reverse reaction becomes faster. The forward. reaction will continue to slow and the reverse reaction will continue to increase until they are the same.Then the situation will be at equilibrium.

8 0

3 years ago

128g of sulphur are burned in excess oxygen. What mass of sulphur dioxide forms? S + O2 --> SO2 *

Rasek [7]

Mass of Sulphur dioxide : 256 g

<h3>Further explanation</h3>

Given

Reaction

S + O2 --> SO2 *

Required

Mass of Sulphur dioxide

Solution

mol of Sulphur (Ar=32 g/mol) :

mol = mass : Ar

mol = 128 : 32

mol = 4

From the equation, mol ratio S : SO2 = 1 : 1, so mol SO2 = 4

Mass of SO2 :

mass = mol x MW SO2

mass = 4 x 64

mass = 256 g

5 0

3 years ago

The reaction 2NO(g)+Cl2(g)→2NOCl(g) is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate o

Luba_88 [7]

Answer : The rate of change of the total pressure of the vessel is, 10.5 torr/min.

Explanation : Given,

$\frac{d[NO]}{dt}$ =21 torr/min

The balanced chemical reaction is,

$2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)$

The rate of disappearance of $NO$ = $-\frac{1}{2}\frac{d[NO]}{dt}$

The rate of disappearance of $Cl_2$ = $-\frac{d[Cl_2]}{dt}$

The rate of formation of $NOCl$ = $\frac{1}{2}\frac{d[NOCl]}{dt}$

As we know that,

$\frac{d[NO]}{dt}$ =21 torr/min

So,

$-\frac{d[Cl_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}$

$\frac{d[Cl_2]}{dt}=\frac{1}{2}\times 21torr/min=10.5torr/min$

And,

$\frac{1}{2}\frac{d[NOCl]}{dt}=\frac{1}{2}\frac{d[NO]}$

$\frac{d[NOCl]}{dt}=\frac{d[NO]}=21torr/min$

Now we have to calculate the rate change.

Rate change = Reactant rate - Product rate

Rate change = (21 + 10.5) - 21 = 10.5 torr/min

Therefore, the rate of change of the total pressure of the vessel is, 10.5 torr/min.

8 0

3 years ago