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KonstantinChe [14]
4 years ago
11

Cubic centimeter (cm^3) has the same volume as a

Chemistry
1 answer:
Paraphin [41]4 years ago
6 0

Answer:

1 cc=1 ml=0.001 liter

Explanation:

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lukranit [14]

Answer:

c:the spin of the earth is the answer

6 0
3 years ago
Why displacemet reaction are useful
ANEK [815]
Displacement reactions are useful for thermite welding, steel making, extraction of metals and relief from acid indigestion.
3 0
4 years ago
What type of coloration do the stonefish and oscellated frog fish have
dusya [7]
The stonefish is brown most of the time and blends with the sea floor. The oscellated frogfish is different colors and it blends in with corl
6 0
3 years ago
At 25 °c, only 0.0100 mol of the generic salt ab2 is soluble in 1.00 l of water. what is the ksp of the salt at 25 °c? ab2(s)↽−−
Assoli18 [71]
Where the solubility product Ksp is applied where salts don't fully dissolve in a solvent.

and when the reaction equation is:

AB2(s) ↔ A2+(Aq)  + 2 B-(aq)

so we have the Ksp expression = [A2+][B-]^2

when we assume [A2+] = X = 0.01 M 


and [B-] = 2X = 2*0.01 M = 0.02 M

So by substitution:

Ksp = 0.01 * (0.02)^2

       = 4 x 10^-6
4 0
3 years ago
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
Katena32 [7]

Answer:

ΔH°r = -483.64 kJ

Explanation:

Let's consider the following balanced equation.

2 H₂(g) + O₂(g)  ⇒ 2 H₂O(g)

We can calculate the standard enthalpy change of the reaction (ΔH°r) using the following expression.

ΔH°r = ∑ΔH°f(p) × np - ∑ΔH°f(r) × nr

where

ΔH°f: standard heat of formation

n: moles

p: products

r: reactants

ΔH°r = ΔH°f(H₂O(g)) × 2 mol - ΔH°f(H₂(g)) × 2 mol - ΔH°f(O₂(g)) × 1 mol

ΔH°r = (-241.82 kJ/mol) × 2 mol - 0 kJ/mol × 2 mol - 0 kJ/mol × 1 mol

ΔH°r = -483.64 kJ

4 0
3 years ago
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