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2 years ago

What determines the type of igneous rock that forms from magma?

Physics

2 answers:

valentina_108 [34]2 years ago

8 0

Answer:

c. Magma composition and cooling rate

Explanation:

Igneous rocks form when magma (molten rock) cools and crystallizes, either at volcanoes on the surface of the Earth or while the melted rock is still inside the crust.

drek231 [11]2 years ago

5 0

Answer: C

Explanation:

(Magma composition and cooling rate)

Igneous rocks are formed by cooling magma. The location of the formation of the rock, as well as how fast the magma cools will determine the type of igneous rock. Intrusive rocks form from the cooling of magma deep beneath the earth's surface. Since this occurs below the earth's surface, the magma will cool very slowly.

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What is the impact of roller coaster on human's body

Sindrei [870]

Explanation:

These brain chemicals, including adrenaline, dopamine and cortisol, stimulate a natural high and give you a boost of energy that makes you feel more alert, alive and able to scream your lungs out

8 0

3 years ago

Light traveling from water to a gemstone strikes the surface at an angle of 80.0º and has an angle of refraction of 15.2º . (a)

7nadin3 [17]

Answer:

The the speed of light in the gemstone is $v= 0.599*10^8 m/s$

The unreasonable thing about this is that the speed of ligth in the gemstone is too low

the speed is 19% of the speed of light which is very low

One main unreasonable or inconsistent factor is that the assumption that the differnce between the angle of incidence and angle of refraction is very large

Explanation:

From the question we are told that

The angle of incidence $i = 80^o$

The angle of refraction $r = 15.2^o$

From Snell's law we have ,

$n_1 sin \theta_1 = n_2 sin \theta_2$

Where $n_1$ is the refractive index of the first medium (water) with a constant value of $n_1 = 1..333$

$n_2$ is the refractive index of the second medium (gem stone)

$\theta_1$ is the angle between the beam and perpendicular surface of the first medium

$\theta_2$ is the angle between the beam an the perpendicular surface of the second medium

Making the $n_2$ the subject of the formula

$n_2 = n_1 \frac{sin \theta_1}{sin \theta_2}$

$= (1.333)(\frac{sin (80.0)}{sin 15.2} )$

$= 5.007$

Generally refractive index of a material is mathematically represented

$n = \frac{c}{v}$

Where c is the speed light

v is the speed of light observed in a medium

Making v the subject

$v = \frac{c}{n}$

substituting value for gem stone

$v = \frac{3.0*10^8}{5.007}$

$v= 0.599*10^8 m/s$

7 0

3 years ago

A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant plane. If 20 oscillations are complete

katrin2010 [14]

Answer:

7.50 m/s^2

Explanation:

The period of a pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$ (1)

where

L = 0.600 m is the length of the pendulum

g = ? is the acceleration due to gravity

In this problem, we can find the period T. In fact, the frequency is equal to the number of oscillations per second, so:

$f=\frac{N}{t}=\frac{20}{35.5 s}=0.563 Hz$

And the period is the reciprocal of the frequency:

$T=\frac{1}{f}=\frac{1}{0.563 Hz}=1.776 s$

And by using this into eq.(1), we can find the value of g:

$g=\frac{4 \pi^2 L}{T^2}=\frac{4 \pi^2 (0.600 m)}{(1.776 s)^2}=7.50 m/s^2$

6 0

3 years ago

A particle moving on a circle has a velocity of 5 m/s and a normal acceleration of 10 m/s^2. What is the radius of the circle?

dybincka [34]

Answer:

Radius of the circle will be 2.5 m

Explanation:

We have given velocity of particle moving in the circle v = 5 m/sec

Acceleration of particle in the circle $a=10m/sec^2$

We have to find the radius of the circle

We know that acceleration is given by $a=\frac{v^2}{r}$

So $10=\frac{5^2}{r}$

$r=\frac{25}{10}=2.5m$

So radius of the circle will be 2.5 m

3 0

3 years ago

How dose an atom change if all of its electrons are removed

cluponka [151]

Answer:

The atom becomes a positively charged ion.

Explanation:

The building blocks of an atom are protons, neutrons, and electrons.
The protons and neutrons present in the core of the atom are called nucleus.
The electrons are scattered in an ordered way around the nucleus.
The protons are positively charged and the electrons are negatively charged particles. The neutrons do not possess any charges.
Binding energy is supplied to the atom to remove an electron.
It is possible to remove the electrons of the lighter elements.
When an electron is removed from the hydrogen atom. It becomes positively charged ion or simply proton.
When all of the electrons are removed from the helium atom, it becomes a positively charged α particle.
It is practically very difficult to remove all of the electrons from the heavier elements.
When all of the electrons are removed from an atom it becomes an unstable positively charged ion.

7 0

3 years ago