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Setler79 [48]
2 years ago
12

Which one of the following environments will sound not travel through?

Physics
1 answer:
Eduardwww [97]2 years ago
7 0
The answer is d. Vacuum

Sound waves need a molecul to travel through. Gas , solid, annd liquid provide that medium.

But vacuum is just an empty space withour any moleculs in it.

Thats why in space, no one can hear you scream. Because it simply not physicsly possible
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A uniformly charged sphere has a total charge of 300uc and a radius of 8cm. Find the electric field density at A point 16cm from
s2008m [1.1K]

E = <u>kQ</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

(r + h)²

where,

k = 9 × 10^9Nm²C^-2

Q = total charge, 300uC = 300 × 10^ -6C

r = 8 × 10^ -2m

h = 16 × 10^ -2m

then,

E = <u>9</u><u>e</u><u>9</u><u> </u><u>*</u><u> </u><u>3</u><u>0</u><u>0</u><u>e</u><u>^</u><u>-</u><u>6</u><u> </u><u> </u><u> </u><u> </u>

(8e^-2 + 16e^-2)²

E = 4687500N/C

6 0
2 years ago
What percentage of the original kinetic energy is convertible to internal energy?
schepotkina [342]
There would be very less percentage loss<span> of the kinetic energy during </span>the conversion<span> to internal energy, assuming that there is less air in the </span>surroundings<span>. Also, the friction will contribute to the conversion where if it is, the percentage loses is negligible.</span>
7 0
3 years ago
A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound
NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

To find the frequency of the sound produced by the pipe you use the following formula:

f_n=\frac{nv_s}{4L}

n: number of the harmonic = 3

vs: speed of sound = 340 m/s

L: length of the pipe = 2.5 m

You replace the values of n, L and vs in order to calculate the frequency:

f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz

hence, the frequency of the third overtone is 102 Hz

8 0
3 years ago
A rural mail carrier logged the mileage on the odometer at the start of the mail route as 31,500 miles. After 6.5 hours, the car
dusya [7]

Answer:32.77\ mi/hr

Explanation:

Given

Initially Reading on the odometer is 31,500\ miles

Final reading on the odometer is 31,713\ miles

Time taken is t=6.5\ hr

average velocity =\dfrac{\text{Displacement}}{\text{time}}

v_{avg}=\dfrac{31713-31500}{6.5}

v_{avg}=\dfrac{213}{6.5}

v_{avg}=32.77\ mi/hr

Thus the average velocity of mail truck is 32.77\ mi/hr

8 0
3 years ago
Physics help please!
Oliga [24]

Answer:

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Explanation:

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6 0
3 years ago
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