
- A ball is dropped from a height = H
- The total distance covered in last second of its motion is equal to the distance covered in first 3 second .

- The height of the journey .

We have know that,

Where,
- u = initial velocity = 0m/s
[Note :- Here, acceleration is ‛acceleration due to gravity’ .]
=> S = 1/2 × 10 × (3)^2
=> S = 5 × 9
=> S = <u>4</u><u>5</u><u>m</u> -----(1)
✒ If the ball takes ‛n’ second to fall the ground, then distance covered in nth second is,

=> Sn = 0 + 10/2 (2 × n - 1)
=> Sn = 5 (2n - 1)
=> Sn = 10n - 5 -----(2)
Therefore,
=> 10n = 45 + 5
=> n = 50/10
=> n = <u>5</u>
Now put the value of ‛n = 5’ in equation(2), we get
=> Sn = 10 × 5 - 5
=> Sn = 50 - 5
=> <u>Sn</u><u> </u><u>=</u><u> </u><u>4</u><u>5</u><u>m</u>
The height of the journey is “ <u>4</u><u>5</u><u>m</u> ” .
Answer:No
Explanation:The amount of mass is the amount of matter in an object if it is contracted the mass stays the same, it is just more dense
Chemical energy stored in the compounds caked on the head of the match, and later the
chemical energy stored in the wood, was released in the form of heat and light when the
chemical compounds got hot enough.
The correct answer would be "He brought one serving to his neighbor's house, and stored the other two servings in the refrigerator. Devon ate one more serving or spaghetti the following day."
Previous results tell us the speed (v) is given in terms of the coefficient of friction (k) and the radius of the curve (r) as
v = √(kgr)
v = √(0.20·9.8 m/s²·50 m)
= 7√2 m/s ≈ 9.90 m/s