All categories

3 years ago

What is the difference between dry and drag force

1 answer:

8 0

There is a difference between dragand friction. Friction is relatively constant at different velocities whiledrag increases with speed. Forexample, when you rub your hands together at different speeds, the force of friction remains the same although the heat generated will vary.

You might be interested in

A wheelchair ramp needs to be 8 inches high how long does it have to be to have a mechanical advantage of 5

Nastasia [14]

MA = (Effort Distance)/(Effort Resistance) = L/H

L = MA * H = 5 * 8" = 40"

8 0

3 years ago

Which statement best describes the energy changes that occur while a child is riding on a sled down a steep, snow-covered hill?

svp [43]

The answer is C, because they moved from a stand still to down the hill

4 0

4 years ago

Calculate the focal length of the mirror formed by the convex side of a shiny spoon that has a 1.54 cm radius of curvature. (b)

blondinia [14]

Explanation:

It is given that,

Radius of curvature of the mirror, R = 1.54 cm

(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :

$R=2f$

f = focal length of the mirror

$f=\dfrac{1.54\ cm}{2}$

f = 0.77 cm

(b) The power of mirror is given by the reciprocal of focal length i.e.

Power, $P=\dfrac{1}{f}$

P = 1.29 diopters

Hence, this is the required solution.

6 0

4 years ago

A rotating space station is said to create "artificial gravity" - a loosely-defined term used for an acceleration that would be

FrozenT [24]

Answer:

$\omega=0.31\frac{rad}{s}$

Explanation:

The artificial gravity generated by the rotating space station is the same centripetal acceleration due to the rotational motion of the station, which is given by:

$a_c=\frac{v^2}{r}(1)$

Here, r is the radius and v is the tangential speed, which is given by:

$v=\omega r(2)$

Here $\omega$ is the angular velocity, we replace (2) in (1):

$a_c=\frac{(\omega r)^2}{r}\\\\a_c=\omega^2r$

Recall that $r=\frac{d}{2}=\frac{200m}{2}=100m$ .

Solving for $\omega$ :

$\omega=\sqrt{\frac{a_c}{r}}\\\omega=\sqrt{\frac{9.8\frac{m}{s^2}}{100m}}\\\omega=0.31\frac{rad}{s}$

3 0

4 years ago

ANSWER QUICKLY PLEASE <3

Sladkaya [172]

The forces on one of the wires will be 0.000264 N.It is the field sensed around a moving electric charge that gives rise to the magnetic force.

<h3>What is a magnetic field?</h3>

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.

The given data in the problem is;

I is the current = 6.50 A

B is the magnetic field=f 2.71 X 10⁻⁵ T

The force on the wire is;

$\rm F= BIL \\\\\ F=2.71 \times 10^{-5} \ T \times 6.50 \ A \times 1.50 \ m \\\\\ F=0.000264225 \ N$

Hence, the force on one of the wires will be 0.000264 N.

To learn more about the magnetic field refer to the link;

brainly.com/question/19542022

#SPJ1

6 0

2 years ago