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babymother [125]
3 years ago
13

What does it mean when there is a physical change?

Chemistry
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

The matter has changed size, shape, or form.

Explanation:

A new substance that is formed is creation.

if the matter changed from one substance to another this is called a chemical reaction.

Surely not. It won't change the molecular level.

Hope that helps.

You might be interested in
A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera
Grace [21]

Answer: The initial temperature of the iron was 515^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of iron = 360 g

m_2 = mass of water = 750 g

T_{final} = final temperature = 46.7^0C

T_1 = temperature of iron = ?

T_2 = temperature of water = 22.5^oC

c_1 = specific heat of iron = 0.450J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]

T_i=515^0C

Therefore, the initial temperature of the iron was 515^0C

4 0
3 years ago
Help please! please answer with a good answer ​
KonstantinChe [14]

Answer:

what the heck what is that?

Explanation:

5 0
3 years ago
Need help figuring out these questions did I do them right
Bas_tet [7]

Answer:

The answer to your question is: more less

Explanation:

I suggest you these answers:

a)     PCl₅ (s)     ⇒    PCl₃ (s)  + Cl₂ (g)

b)  ZnBr₂ (aq) + Li₃CO₃ (aq)  ⇒  ZnCO₃ (s)  + LiBr (aq)

c) C₂H₄  + O₂   ⇒    CO₂ (g) + H₂O (l)

Do you have to balance them?

8 0
3 years ago
Calculate the pH of a solution that is 0.235M benzoic acid and 0.130M sodium benzoate, a salt whose anion is the conjugate base
lesantik [10]

Hello!

We have the following data:

ps: we apply Ka in benzoic acid to the solution.

[acid] = 0.235 M (mol/L)

[salt] = 0.130 M (mol/L)

pKa (acetic acid buffer) =?

pH of a buffer =?

Let us first find pKa of benzoic acid, knowing that Ka (benzoic acid) = 6.20*10^{-5}

So:

pKa = - log\:(Ka)

pKa = - log\:(6.20*10^{-5})

pKa = 5 - log\:6.20

pKa = 5 - 0.79

\boxed{pKa = 4.21}

Now, using the abovementioned data for the pH formula of a buffer solution or (Henderson-Hasselbalch equation), we have:

pH = pKa + log\:\dfrac{[salt]}{[acid]}

pH = 4.21 + log\:\dfrac{0.130}{0.235}

pH = 4.21 + log\:0.55

pH = 4.21 + (-0.26)

pH = 4.21 - 0.26

\boxed{\boxed{pH = 3.95}}\end{array}}\qquad\checkmark

Note:. The pH <7, then we have an acidic solution.

I Hope this helps, greetings ... DexteR! =)

8 0
2 years ago
What is an orderly, three dimensional arrangement formed by ions called?
Morgarella [4.7K]
I believe it is a crystal, read it in a chemistry book over last summer so might be off
3 0
3 years ago
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