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4 years ago

Gas Laws

Chemistry

1 answer:

Scorpion4ik [409]4 years ago

6 0

Answer:

The pressure of the gas increases by the four times.

Explanation:

According to the Gay-Lussac's law

The relationship between pressure and temperature is as follows.

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$ \

From the given data, we considered 1 is a initial temperature and 4 is final temperature. Initial pressure is considered as $P_{1}$ .

Let's find the final pressure of the gas.

$P_{2}=\frac{P_{1}T_{2}}{T_{1}}$

Substitute the temperature value.

$P_{2}=\frac{P_{1}(4)}{1}$

$P_{2}=4P_{1}$

Therefore, The pressure of the gas increases by the four times.

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According to the equation you have 1 mole of C2H4 and 3 moles of O2.

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1/270L = 3/x

x = 3(270) / 1

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What is the molarity of a solution prepared by dissolving 36. 0 g of naoh in enough water to make 1. 50 l of solution?

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0.6 mol / L is the molarity of a solution prepared by dissolving 36. 0 g of NaOH in enough water to make 1. 50 l of solution.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another term for molarity.

The ratio employed to indicate the solution's concentration is called its molarity. Understanding a solution's molarity is important since it allows you to determine the actual concentration as well as whether the solution is diluted or concentrated.

Amount of NaOH = 36. 0 g

Amount of water = 1. 50 L

1 mol of NaOH = 40 g,

Moles of NaOH = 36. 0 / 40 g = 0.9 mol NaOH

Molarity of a solution = moles of solute / Liters of solution

Molarity of a solution = 0.9 / 1.50

Molarity of a solution = 0.6 mol / L

To know more about Molarity refer to: brainly.com/question/8732513

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1 year ago

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3 years ago

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) + H2O (l) â†’ Ca(OH)2 (s) In a p

dybincka [34]

Answer:

The option closest to the percentage yield is option;

d. 81.1

Explanation:

The given chemical equation of the reaction is presented as follows;

CaO (s) + H₂O (l) → Ca(OH)₂

The mass of CaO in the experiment, m = 2.00 g

The volume of water with which the CaO was reacted = Excess volume of water

Number of moles = Mass/(Molar mass)

The mass of Ca(OH)₂ recovered, actual yield = 2.14 g

The molar mass of CaO = 56.0774 g/mol

The number of moles of CaO in the reaction, n₁ = 2.00 g/(56.0774 g/mol ≈ 0.036 moles

The molar mass of Ca(OH)₂ = 74.093 g/mol

The number of moles of Ca(OH)₂ in the reaction, n₂ = 2.14 g/(74.093 g/mol) ≈ 0.029 moles

From the given chemical reaction, one mole of CaO reacts with one mole of H₂O to produce one mole of Ca(OH)₂

Therefore, 0.036 moles of CaO will produce 0.036 moles of Ca(OH)₂

Mass = Number of moles × Molar mass

The mass of 0.036 moles of Ca(OH)₂ ≈ 0.036 moles × 74.093 g/mol = 2.667348 grams

∴ The theoretical yield of Ca(OH)₂ = 2.667348 grams

$Percentage \ yield = \dfrac{Actual \ yield}{Theoretical \ yield} \times 100 \%$

The percentage yield = (2.14 g)/(2.667348 grams) × 100 = 80.23%

Therefore, the option which is closest is option d. 81.1.

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3 years ago