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3 years ago

Gas Laws

Chemistry

1 answer:

Scorpion4ik [409]3 years ago

6 0

Answer:

The pressure of the gas increases by the four times.

Explanation:

According to the Gay-Lussac's law

The relationship between pressure and temperature is as follows.

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$ \

From the given data, we considered 1 is a initial temperature and 4 is final temperature. Initial pressure is considered as $P_{1}$ .

Let's find the final pressure of the gas.

$P_{2}=\frac{P_{1}T_{2}}{T_{1}}$

Substitute the temperature value.

$P_{2}=\frac{P_{1}(4)}{1}$

$P_{2}=4P_{1}$

Therefore, The pressure of the gas increases by the four times.

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