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vovikov84 [41]
3 years ago
15

Gas Laws

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
6 0

Answer:

The pressure of the gas increases by the four times.

Explanation:

According to the Gay-Lussac's law

The relationship between pressure and temperature is as follows.

\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}\

From the given data, we considered 1 is a initial temperature and 4 is final  temperature. Initial pressure is considered as P_{1}.

Let's find the final pressure of the gas.

P_{2}=\frac{P_{1}T_{2}}{T_{1}}

Substitute the temperature value.

P_{2}=\frac{P_{1}(4)}{1}

P_{2}=4P_{1}

Therefore, The pressure of the gas increases by the four times.

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