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3 years ago

Gas Laws

Chemistry

1 answer:

Scorpion4ik [409]3 years ago

6 0

Answer:

The pressure of the gas increases by the four times.

Explanation:

According to the Gay-Lussac's law

The relationship between pressure and temperature is as follows.

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$ \

From the given data, we considered 1 is a initial temperature and 4 is final temperature. Initial pressure is considered as $P_{1}$ .

Let's find the final pressure of the gas.

$P_{2}=\frac{P_{1}T_{2}}{T_{1}}$

Substitute the temperature value.

$P_{2}=\frac{P_{1}(4)}{1}$

$P_{2}=4P_{1}$

Therefore, The pressure of the gas increases by the four times.

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What is the mass of 6.02 x 1023 particles of rubidium carbonate

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Answer:

Explanation:

84.97

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3 years ago

Propane gas, C3H8, is sometimes used as a fuel. In order to measure its energy output as a fuel a 1.860 g sample was combined wi

lisov135 [29]

Answer:

The heat of the reaction is 105.308 kJ/mol.

Explanation:

Let the heat released during reaction be q.

Heat gained by water: Q

Mass of water ,m= 1kg = 1000 g

Heat capacity of water ,c= 4.184 J/g°C

Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C

Q=mcΔT

Heat gained by bomb calorimeter =Q'

Heat capacity of bomb calorimeter ,C= 4.643 J/g°C

Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C

Q'=CΔT'=CΔT

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

q= -(Q+Q')

q = -mcΔT - CΔT=-ΔT(mc+C)

$q=-1.061^oC(1000 g\times 4.184J/g^oC+4.643 J/^oC )=-4,444.15J=-4.444 kJ$

Moles of propane = $\frac{1.860 g}{44 g/mol}=0.0422 mol$

0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.

The heat of the reaction will be:

$\frac{4.444 kJ}{0.0422 mol}=105.308 kJ/mol$

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3 years ago

Identify the Bronsted-Lowry acid, the Bronsted-Lowry base, the conjugate acid and the conjugate base for each of the following r

Vlad1618 [11]

Answer:

Acids → H₂CO₃ from equilibrium 1 and water, from equilibrium 2.

Bases → Water from equilibrium 1 and ammonia from equilibrium 2.

In 1st equilibrium, H₃O⁺ is the conjugate acid and HCO₃⁻ the conjugate base.

In 2nd equilibrium, NH₄⁺ is the conjugate acid, and OH⁻, the conjugate base.

Explanation:

By the Bronsted-Lowry you know that acids are the one that release protons and base are the ones that catch them.

For the first equilibrium:

H₂CO₃(aq) + H₂O(l) ⇄ H₃O⁺(aq) + HCO₃⁻(aq)

Carbonic acid is the acid → It donates the proton to water, so the water becomes the base. As H₂CO₃ is the acid, the bicarbonate is the conjugate base (it can accept the proton from water to become carbonic acid, again) and the hydronium is the conjugate acid (it would release the proton to become water).

For the second equilibrium:

NH₃(aq) + H₂O(l) ⇄ NH₄⁺ (aq) + OH⁻(aq)

This is the opposite situation → Water relase the proton to ammonia, that's why water is the acid and NH₃, the base (it accepted to become ammonium). The NH₄⁺ is the conjugate acid (it can release the H⁺ to become ammonia) and the OH⁻ is the conjugate base (It can accept the proton to become water, again).

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3 years ago

A mixture is made by combining 1.62 lb of salt and 5.20 lb of water.

WINSTONCH [101]

Answer:

23.8

Explanation:

Formula

weight % = weight of solute/ weight of solution x 100

weight of solution = weight of salt + weight of water

weight of solution = 1.62 lb + 5.20 lb = 6.82 lb

weight % = 1.62 / 6,82 x 100

weight % = 0.238 x 100

weight % = 23.8

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pav-90 [236]

I believe it becomes gasses the hotter it gets

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3 years ago