Question

The magnetic moment of a rectangular loop that carries 6 A and has dimensions are 0.04 m × 0.08 m is 12 Am2. How many turns are present?

Answer 1

Answer:

The number of turns present in the loop are 625 turns.

Explanation:

Given;

current on the rectangular loop, I = 6A

Dimension of the rectangular loop, L x B = 0.04 m × 0.08 m

Magnetic moment of the loop, Pm = 12 Am²

Area of the rectangular loop, A =  L x B = 0.04 m × 0.08 m = 0.0032 m²

The magnetic moment of plane carrying coil/loop is given as;

Pm = NIA

Where;

N is the number of turns

A is the area of the loop

I is the current on the loop

$N = \frac{P_m}{IA} \\\\N = \frac{12}{6*0.0032}\\\\N = 625 \ turns$

Therefore, the number of turns present in the loop are 625 turns.