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inessss [21]
3 years ago
10

The magnetic moment of a rectangular loop that carries 6 A and has dimensions are 0.04 m × 0.08 m is 12 Am2. How many turns are

present?
Physics
1 answer:
Paul [167]3 years ago
5 0

Answer:

The number of turns present in the loop are 625 turns.

Explanation:

Given;

current on the rectangular loop, I = 6A

Dimension of the rectangular loop, L x B = 0.04 m × 0.08 m

Magnetic moment of the loop, Pm = 12 Am²

Area of the rectangular loop, A =  L x B = 0.04 m × 0.08 m = 0.0032 m²

The magnetic moment of plane carrying coil/loop is given as;

Pm = NIA

Where;

N is the number of turns

A is the area of the loop

I is the current on the loop

N = \frac{P_m}{IA} \\\\N  = \frac{12}{6*0.0032}\\\\N = 625 \ turns

Therefore, the number of turns present in the loop are 625 turns.

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