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coldgirl [10]
3 years ago
13

10.6 grams if NA2CO3 is dissolved in water to make 1.25 liters of solution. What is the molarity of the solution?

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

Answer::Molarity = 0.08 MExplanation:Given data:Mass of sodium carbonate = 10.6 gVolume of water = 1.25 LMolarity of solution = ?Solution:First of ... 10.6 grams of Na2CO3 is dissolved in water to make 1.25 liters of solution.

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What is the limiting reactant when 20g CH4 react with 15g H20?
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Answer:

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Explanation:

  • It is clear from the balanced equation:

<em>CH₄ + 2H₂O → CO₂ + 4H₂.</em>

that 1.0  mole of CH₄ reacts with 2.0 moles of H₂O to produce 1.0 mole of CO₂ and 4.0 moles of H₂.

  • To determine the limiting reactant, we should calculate the no. of moles of (20 g) CH₄ and (15 g) H₂O using the relation:

<em>n = mass/molar mass</em>

<em></em>

no. of moles of CH₄ = mass/molar mass = (20 g)/(16 g/mol) = 1.25 mol.

no. of moles of H₂O = mass/molar mass = (15 g)/(18 g/mol) = 0.833 mol.

  • <em>from the balanced reaction, 1.0  mole of CH₄ reacts with 2.0 moles of H₂O.</em>

So, from the calculated no. of moles: 0.4167 mole of CH₄ reacts completely with 0.833 mole of H₂O and the remaining of CH₄ will be in excess.

<u><em>So, the limiting reactant is H₂O.</em></u>

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