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3 years ago

Can someone please describe surface tension to me. Please don't give me the dictionary definition. Thank you

Physics

1 answer:

11111nata11111 [884]3 years ago

6 0

Surface tension - My definition -

It's exactly what it says - The tension of a surface with a liquid (such as water), caused by the attraction of the surfaces layer ---- I hope this helps ---- I actually did research it and got some of this from a dictionary, but I changed some of it, too.... Sorry if this doesn't help :)

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3 years ago

How do very high density objects appear in an ultrasound?

evablogger [386]

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3 years ago

What is the magnitude of the force required to stretch a 20 cm-long spring, with a spring constant of 100 N/m, to a length of 21

GalinKa [24]

The correct answer to the question is: 1 N.

EXPLANATION:

As per the question, the spring constant or the force constant of the spring is given as k = 100 N/m.

The original length of the spring L = 20 cm.

The stretched length of the spring L'= 21 cm.

Hence, the change in length will be-

∆L = L' - L

= 21 cm - 20 cm

= 1 cm

= 0.01 m

We are asked to calculate the magnitude of force acting on the spring .

From Hooke's law, we know that the restoring force that acts on the spring is proportional to the distance .

Mathematically it can be written as -

F = - kx.

Here, k is the force constant.

x is the change in length due to compression or elongation.

The negative sign is due to the fact that it is opposite to the applied force.

Hence, the applied force on the spring is calculated as -

F = kx

= k × ∆L

= 100 N/ m × 0.01 m

= 1 N.

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8 0

3 years ago

A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa

AVprozaik [17]

To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.

For the case of the magnetic moment of a loop we have to,

$\mu = IA$

Where

I = Current

A = Area of the loop

Moreover the torque exerted by the magnetic field is defined as,

$\tau = IAB$

Where,

I = Current

A = Area of the loop

B = Magnetic Field

PART A) First we need to find the perimeter, then

$P = 2\pi r$

$r = \frac{P}{2\pi}$

$r = \frac{1.9}{2\pi}$

$r = 0.3025m,$

The total Area of the loop would be given as,

$A = \pi r^2$

$A = \pi 0.3025^2$

$A = 0.287m^2$

Substituting at the equation of magnetic moment we have

$\mu = (16*10^{-3})(0.287)$

$\mu = 4.58*10^{-3} A.m^2$

Therefore the magnetic moment of the loop is $4.58*10^{-3}Am^2$

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$\tau = IAB$

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3 years ago

The first-order decomposition of cyclopropane has a rate constant of 6.7 × 10–4 s–1. If the initial concentration of cyclopropan

Ket [755]

Answer:

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Explanation:

For first order decomposition,

rate constant k = 1/t x ln a / (a - x )

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6.7 x 10 ⁻⁴ = 1/644 x ln 1.33/b

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4 years ago