100%-64% to obtain the remaining% of the isotopes
= 36%
then,
atimic weight= (64×51) + (36×51)
=5100 amu
Answer:
16 mol O2
Explanation:
CO + 2 O2 -> 2 CO2
1 mol CO -> 2 mol O2
8 mol CO -> x
x= (8 mol CO * 2 mol O2)/1 mol CO
x= 16 mol O2
∆E=155kJ
Check attachment
