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tekilochka [14]
3 years ago
11

Which expression has a value of 15 when n = 7? 43 minus 5 n 3 n minus 5 6 n minus 28 19 minus StartFraction 28 Over n EndFractio

n
Mathematics
2 answers:
skad [1K]3 years ago
8 0

Answer:

19- 28 0ver n is the expression with value of 15 when n = 7.

Step-by-step explanation:

andrey2020 [161]3 years ago
4 0

Answer:

19-\dfrac{28}{n} is the expression with value of 15 when n = 7.

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

43-5n

Substituting the value of n,

43-5\left(7\right)

Simplifying,

43-35=8

Since the value of the expression is 8 which is not equal 15.

Hence expression 43-5n does not have value of 15 when n = 7.

Expression 2:

3n-5

Substituting the value of n,

3\left(7\right)-5

Simplifying,

21-5=16

Since the value of the expression is 16 which is not equal 15.

Hence expression 3n-5 does not have value of 15 when n = 7.

Expression 3:

6n-28

Substituting the value of n,

6\left(7\right)-28

Simplifying,

42-28=14

Since the value of the expression is 14 which is not equal 15.

Hence expression 6n-28 does not have value of 15 when n = 7.

Expression 4:

19-\dfrac{28}{n}

Substituting the value of n,

19-\dfrac{28}{7}

Simplifying,

19-4=15

Since the value of the expression is 15 which is equal 15.

Hence expression 19-\dfrac{28}{n} has the value of 15 when n = 7.

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12345 [234]

Given:

The rate of interest on three accounts are 7%, 8%, 9%.

She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

Total interest for the year is $150.

To find:

Amount invested on each rate.

Solution:

Let x be the amount invested at 7%. Then,

The amount invested at 8% = 2x

The amount invested at 9% = 3x

Total interest for the year is $150.

x\times \dfrac{7}{100}+2x\times \dfrac{8}{100}+3x\times \dfrac{9}{100}=150

Multiply both sides by 100.

7x+16x+27x=15000

50x=15000

Divide both sides by 50.

x=\dfrac{15000}{50}

x=300

The amount invested at 7% is 300.

The amount invested at 8% is

2(300)=600

The amount invested at 9% is

3(300)=900

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.

4 0
3 years ago
Ask questions slove for x 5(x-3)=15
Pavel [41]

Answer:

Step-by-step explanation:

Your answer is 6

4 0
3 years ago
An architect built a scale model of a sports stadium using a scale in which 2 inches represents 30 feet. The height of the sport
bija089 [108]
The height of the model in inches would be 6. if you multiply 30 until it reaches 180 you will have 6.
7 0
3 years ago
45% of the 647 students at Royal Oak High attended the football game. How many students did not attend?
Lostsunrise [7]
First multiply
.45*647= 291.15
291.15 is the number of people that attended 
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3 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST TO BEST RESPONSE!
Monica [59]

You are given the X value, replace x with 2 in the first equation to solve for y:

y=2x +3

y = 2(2) +3

y = 4+3

y = 7

Now replace y with 7 and x iwth 2 in the second equation and solve for k:

y = -x +k

7 = -2 +k

Add 2 to both sides:

9 = k

so k = 9

The point is given as k-2, which is 9-2 = 7, which is what y equals in the first equation.

K = 9

5 0
4 years ago
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