The following is produced when propane (C₃H₈) is combusted completely : H₂O
<h3>Further explanation </h3>
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Hydrocarbon combustion reactions (especially alkanes) 
For combustion of propane C₃H₈ (n = 3) ⇒ completely(excess O₂) :
C₃H₈+5O₂⇒3CO₂+4H₂O
The products of combustion : CO₂ and H₂O
Answer:
1 is the same 3 is pure substance 4 is different
Explanation:
not sure about 2
Answer:
Explanation
Comment
Normally you would just use m*c*delta T. But the c is the same in both cases, so you need just use m*deltaT
Givens
25 degrees
m = ?
T = 25
t = final temp = 75
93 degrees
m = 250
T = 93
t = final temp = 75
Solution
(t - 25)*m = (93 - t) * 250 Remove the brackets
75*m - 25m = 93*250 - 250*75 Combine the right
m(75 - 25) = 23250 - 250*75
50 m = 23250 - 18750 Combine
50 m = 4500 Divide both sides by 50
50*m/50 = 4500/50
m = 90
Answer: 90 grams are needed.
These answers dont make sense
1. the 2s2 orbital will give one of its electrons to the 2p5 orbital so the configuration would be 1s22s12p6 (2s1 is half filled and 2p6 is completely filled which is a much more stable configuration)
2. Neon does not need to ionize it is a noble gas
Answer:
Gd(g) → 
, 
→ 
, 
→ 
Explanation:
Ionization energy is the energy required to remove an electron from a gaseous atom or ion.
The first ionization energy is the energy required to remove the valence electron(outermost) from a neutral atom:
Gd(g)→
The second ionization energy is the energy required to remove next/second electron from 
ion. The second ionization energy is always higher than the first:
(g) →
The third ionization energy is the energy required to remove third electron from 
ion:
(g) →
