1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vekshin1
3 years ago
13

A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is

low, the penny rides up and down without difficulty. If the frequency is steadily increased, there comes a point at which the penny leaves the surface.A) At what point in the cycle does the penny first lose contact with the piston?midpoint moving uplowest pointhighest pointmidpoint moving downB) What is the maximum frequency for which the penny just barely remains in place for the full cycle?Express your answer with the appropriate units.

Physics
1 answer:
BlackZzzverrR [31]3 years ago
6 0

Answer:

the penny loses contact at the piston's highest point.

f = 2.5 Hz

Explanation:

Concepts and Principles  

1- Newton's Second Law: The net force F on a body with mass m is related to the body's acceleration a by  

∑F = ma                                                          (1)  

2- The maximum transverse acceleration of a particle in simple harmonic motion is found in terms of the angular speed w and the amplitude A as follows:  

a_max = -w^2A                                                (2)  

3- The angular frequency w of a wave is related to the frequency f by:  

w = 2π f                                                              (3)  

Given Data  

- The amplitude of the piston is: A = (4.0 cm) ( 1/ 100 cm)=  0.04 m.  

- The frequency of oscillation of the piston is steadily increased.

Required Data

<em>In part (a), we are asked to determine the point at which the penny first loses contact with the piston.  </em>

<em>In part (b), we are asked to determine the maximum frequency for which the penny just barely remains in place for a full cycle.  </em>

Solution  

(a)  

The free-body diagram in Figure 1 shows the forces acting on the penny; mi is the gravitational force exerted by the Earth on the penny andrt is the normal contact force exerted by the piston on the penny.  

figure 1 is attached

Apply Newton's second law from Equation (1) in the vertical direction to the penny:  

∑F_y -mg= ma        

Solve for n=m(g+a) The penny loses contact with the surface of the oscillating piston when the normal force n exerted by the piston is zero. So  

0 = m(g + a)

a = —g  

Therefore, the penny loses contact with the piston when the piston starts accelerating downwards. The piston first acceleratesdownward at its highest point and hence the penny loses contact at the piston's highest point.

(b)  

The maximum acceleration of the penny at the highest point of the piston is found from Equation (2):  

a = —w^2A  

where a = —g at the highest point. So  

g = w^2A  

Solve for w:  

w =√g/A

Substitute for w from Equation (3):

2πf =  √g/A

Solve for f :  

f = 1/2π√g/A

Substitute numerical values:  

f = 1/2π√9.8 m/s^2/0.04

f = 2.5 Hz

You might be interested in
Which one of the statements below is true about mechanical waves?
TEA [102]
They require a medium to travel through
5 0
2 years ago
ANSWER FOR BRAINLIEST
Nikitich [7]
A (b) would be 42 (c) from x to Y mark me as brainlist thanks
5 0
2 years ago
Can you explain why number 3 is correct?
lukranit [14]
No waves because Q19 waves would going at the surface at regions
7 0
2 years ago
A 120 resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source. what is the current
larisa [96]

Answer:

6 A

Explanation:

First of all, we need to calculate the equivalent resistance of the circuit. The three resistors are connected in parallel, so their equivalent resistance is given by:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}=\frac{1}{120 \Omega}+\frac{1}{60 \Omega}+\frac{1}{40 \Omega}=\frac{3+2+1}{120 \Omega}=\frac{6}{120 \Omega}\\R_T = \frac{120}{6} \Omega

And now we can use Ohm's law to find the current in the circuit:

V=R_T II=\frac{V}{R_T}=\frac{120 V}{\frac{120}{6}\Omega}=6 A

6 0
3 years ago
How does the muscular system help humans maintain posture?
leonid [27]
The muscular system<span> is an </span>organ system<span> composed of </span>skeletal<span>, </span>smooth<span> and </span>cardiac muscles<span>. This system allows movement of the body, maintains posture, and circulates blood throughout the body. 
</span>
>Muscles<span> continually align themselves vertically to </span>help maintain posture.
7 0
2 years ago
Other questions:
  • Mars' atmosphere is mostly made of _____. A. helium B. nitrogen C. water vapor D. carbon dioxide
    11·1 answer
  • During a 0.001 s interval while it is between the plates, the change of the momentum of the electron Δp with arrow is &lt; 0, -8
    8·1 answer
  • Which of the following is an inorganic compound?
    9·2 answers
  • What’s contact force ?
    7·2 answers
  • The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla
    6·1 answer
  • A temperature of 20°C is equivalent to approximately
    9·2 answers
  • If hydrogen and helium are the most abundant elements in the unoverse , then why are living organisms composed primarily of carb
    10·1 answer
  • Buoyant force acts in the opposite direction as the force of
    14·1 answer
  • Kjkrenv rejfkrnfkej erjfnkejrfn jnefkjnfk jekfnrfkj
    6·2 answers
  • 2. An 873 kg dragster accelerates at a rate of 44.6 m/s during a race.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!