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3 years ago

Determine how many Altuves you could travel in a day if you were moving at 45.000 mph all day. Altuve = 1.65 m

Physics

1 answer:

dimaraw [331]3 years ago

8 0

Answer:

The answer is below

Explanation:

Speed is the ratio of total distance traveled to the total time taken. It is given by the formula:

Speed = Distance / time taken

Given that the speed = The polynomial 45.000 mph.

In a day there are 24 hours, hence, the distance traveled is:

Speed = Distance / time taken

45 mph = Distance / 24 hours

Distance = 45 mph × 24 h = 1080 miles

But 1 mile = 1609.34 m

1080 miles = $1080\ miles*\frac{1609.34 \ m}{1\ miles}=1738092\ m$

Given that Altuve = 1.65 m

Hence, the number of Altuve traveled = 1738092 m / 1.65 m = 1053389

1053389 Altuves was traveled

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Answer:

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3 years ago

A ball that has a mass of 0.25 kg spins in a circle at the end of a 1.6 m rope. the ball moves at a tangential speed of 12.2 m/s

NARA [144]

The centripetal force acting on the ball will be 23.26 N.The direction of the centripetal force is always in the path of the center of the course.

<h3>What is centripetal force?</h3>

The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.

The given data in the problem is;

m is the mass of A ball = 0.25 kg

r is the radius of circle= 1.6 m rope

v is the tangential speed = 12.2 m/s

$\rm F_C$ is the centripetal force acting on the ball

The centripetal force is found as;

$\rm F_C = \frac{mv^2}{r} \\\\ F_C = \frac{0.25 \times (12.2)^2}{1.6} \\\\ F_C=23.26\ N$

Hence the centripetal force acting on the ball will be 23.26 N.

To learn more about the centripetal force refer to the link;

brainly.com/question/10596517

4 0

2 years ago

A marble resting near the edge of .90 m high table is given an initial horizontal speed of 1.24 m/s. What will be it’s horizonta

Maru [420]

Answer:

0.53 m

Explanation:

First of all, we have to consider the vertical motion of the ball, in order to find the time it takes for the marble to reach the ground. The initial height is $h=0.90 m$ , the initial vertical velocity is zero, while the acceleration is $g=-9.81 m/s^2$ , so the vertical position at time t is given by

$y(t)=h-\frac{1}{2}gt^2$

By demanding y(t)=0, we find the time t at which the ball reaches the ground:

$0=h-\frac{1}{2}gt^2$

$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(0.9 m)}{9.81 m/s^2}}=0.43 s$

Now we can find the horizontal range of the marble: we know the initial horizontal speed (v=1.24 m/s), we know the total time of the motion (t=0.43 s), and since the horizontal speed is constant, the total distance traveled on the horizontal direction is

$x=vt=(1.24 m/s)(0.43 s)=0.53 m$

8 0

3 years ago

A grating whose slits are 3.2x10^-4 cm apart produces a third-order fringe at a 25.°0 angle. What is the wavelength of light tha

Ber [7]

Answer:

The light used has a wavelenght of 4.51×10^-7 m.

Explanation:

let:

n be the order fringe

Ф be the angle that the light makes

d is the slit spacing of the grating

λ be the wavelength of the light

then, by Bragg's law:

n×λ = d×sin(Ф)

λ = d×sin(Ф)/n

λ = (3.2×10^-4 cm)×sin(25.0°)/3

= 4.51×10^-5 cm

≈ 4.51×10^-7 m

Therefore, the light used has a wavelenght of 4.51×10^-7 m.

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3 years ago

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3 years ago