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vlabodo [156]
3 years ago
7

78 million in standard form

Physics
1 answer:
Leviafan [203]3 years ago
6 0

Answer:

78 million in standard form is 78,000,000

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The hydrogen stored inside a large weather balloon has a mass of 13.558 g. What is the volume of this balloon if the density of
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       (13.558 gm) · (1 L / 0.089 gm)  =  152.34 L  (rounded)
                                        
 (fraction equal to ' 1 ')  ^
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3 years ago
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An object has an acceleration of 6.0 m/s/s. if the net force acting upon this object were doubled, then its new acceleration wou
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F has direct relation with a
then doubling F cause acc. to get double i:e 6×2=12
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Find the energy in Joules required to lift a 55.0 Megagram object a distance of 500 cm.
fredd [130]

Energy to lift something =

               (mass of the object) x (gravity) x (height of the lift).

BUT ...

This simple formula only works if you use the right units.

Mass . . . kilograms
Gravity . . . meters/second²
Height . . . meters

For this question . . .

Mass = 55 megagram = 5.5 x 10⁷ grams = 5.5 x 10⁴ kilograms

Gravity (on Earth) = 9.8 m/second²

Height = 500 cm  =  5.0 meters

So we have ...

Energy = (5.5 x 10⁴ kilogram) x (9.8 m/s²) x (5 m)

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That's quite a large amount of energy ... equivalent to
straining at the rate of 1 horsepower for almost exactly an
hour, or burning a 100 watt light bulb for about 7-1/2 hours.

The reason is the large mass that's being lifted.
On Earth, that much mass weighs about 61 tons.

7 0
3 years ago
An object is most likely to sink in water if
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A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
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From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
6 0
4 years ago
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