Answer:
V = 331.59m/s
Explanation:
First we need to calculate the time taken for the shell fire to hit the ground using the equation of motion.
S = ut + 1/2at²
Given height of the cliff S = 80m
initial velocity u = 0m/s²
a = g = 9.81m/s²
Substitute
80 = 0+1/2(9.81)t²
80 = 4.905t²
t² = 80/4.905
t² = 16.31
t = √16.31
t = 4.04s
Next is to get the vertical velocity
Vy = u + gt
Vy = 0+(9.81)(4.04)
Vy = 39.6324
Also calculate the horizontal velocity
Vx = 1330/4.04
Vx = 329.21m/s
Find the magnitude of the velocity to calculate speed of the shell as it hits the ground.
V² = Vx²+Vy²
V² = 329.21²+39.63²
V² = 329.21²+39.63²
V² = 108,379.2241+1,570.5369
V² = 109,949.761
V = √ 109,949.761
V = 331.59m/s
Hence the speed of the shell as it hits the ground is 331.59m/s
Answer: energy source, path, and load
Explanation:
Answer:
4541.8 J
Explanation:
First we find the mass of benzene available
mass = density x volume
= 0.867 x 34.1
= 29.5647 g
Then we find the amount of heat transferred by two processes:
heat tranferred = heat lost during temp drop + heat lost during freezing
= mcΔT + mL
= 29.5647 x 1.74 x (20.8 - 5.5) + 29.5647 x 127
= 4541.7883434 J
= 4541.8 J
The normal force exerted on the rover when it rests on the surface of the planet be greater is 3,125.22 N.
<h3>
What is normal force?</h3>
A normal force is defined as the force that a surface exerts on an object.
N = W
N = mg
where;
- m is mass of the object
- g is acceleration due to gravity
Normal force is proportional to the weight of an object be considered.
<h3>Normal force of the rover</h3>
N = mg
N = 1,063 kg x 0.3(9.8 m/s²)
N = 3,125.22 N
Thus, the normal force exerted on the rover when it rests on the surface of the planet be greater is 3,125.22 N.
Learn more about normal force here: brainly.com/question/14486416
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The answer is number. The statistic is usually a numerical value that we have obtained through the application of different amthematical algorithms to our datasets. Examples of such algorithms include summary measures, the arithmetic mean, the standard deviation, etc. Statistics are used to give us information about our samples and subgroups, whereas parametrs are numerical values that give us infromation about our population values.