A 2.00-kg block of ice is moving on a frictionless horizontal surface. At t = 0 the block is moving to the right with a velocity
1 answer:
You might be interested in
The length by which the spring got stretched will be 0.08 m. The force is directly propotional to the distance by which the spring stretched.
<h3>What is spring force?</h3>The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is
F = kx
The given data in the problem is;
F is the spring force =200
K is the spring constant= 2500 N/m
x is the length by which spring got stretched =?
The stretch of the spring is found as;
Hence the length by which the spring got stretched will be 0.08 m.
To learn more about the spring force refer to the link;
#SPJ4
Answer:
Given:
mass of the ball m = 0.144 kg
velocity v = 38 m/s
now, change in momentum
P = m v- ( - mv)
= 2 mv
=2 x (0.144) x (38)
= 10.944 kg-m/s
Impulse J= F. Δt
change in momentum is equal to impulse
J = 10.944 kg-m/s
we know force is equal to change in momentum per unit time
F = 13.68 x 10³ N
F = 13.68 kN
Answer:
The sphere
Explanation:
Because it has a smaller inertia (I) value in the explanation in the attached file
