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disa [49]
3 years ago
5

A 2.00-kg block of ice is moving on a frictionless horizontal surface. At t = 0 the block is moving to the right with a velocity

of magnitude 3.00 m/s. (a) Calculate the velocity of the block (magnitude and direction) after a force of 5.00 N directed to the right has been applied for 4.00 s; (b) if instead a force of 7.00 N directed to the left is applied from t=0 to t = 4.00 s, what is the final velocity of the block?
Physics
1 answer:
enyata [817]3 years ago
4 0

Answer:

Explanation:

a )

We shall apply the concept of impulse .

Impulse = force x time = change in momentum

= 5 x 4 = 2 ( V - 3 )  , where V is final velocity of the object

20 = 2V - 6

V = 13 m /s

b )

Impulse applied = - 7 x 4 = - 28 kg m/s ( negative as direction of force is opposite motion )

If v be the final velocity

2 x 3 - 28 = 2 v  ( initial momentum - change in momentum = final momentum )

- 22 = 2v

v = - 11 m /s

object will move with 11 m /s in opposite direction .

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The distance between your school and house is 80 m. In going to your school starting from your
SIZIF [17.4K]

Answer:

a) 2/3 m/s

b) 0.0143 m/s

c) 0.00 m/s

Explanation:

a) 80 m / (2(60) s = 2/3 m/s

b) 2(80) / (3(3600) + (2 + 4)(60)) = 160 / 11,160 = 0.0143 m/s

c) start and end at your house. no displacement, no velocity.

8 0
3 years ago
A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12 s for the
Vesna [10]

Answer:

The height of the cliff from which the ball was dropped from is 224.4m.

\overline{v}={\frac{\Delta x}{\Delta t}}

Given the data in the question;

Initial velocity of the ball;

Time taken by the ball to reach the ground;

Distance or Height of the cliff from which the ball was thrown from;

To get the height of the Cliff, we use the Second Equation of Motion:

Where s is the distance or height,  is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;

Hence, the equation becomes

We substitute the given values into the equation

Therefore, the height of the cliff from which the ball was dropped from is 224.4m

Explanation:

3 0
3 years ago
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if a toaster oven uses 1000 J of electrical energy to produce 800 J of thermal energy, what is the percent efficiency of the toa
ArbitrLikvidat [17]

Answer:

80%

Explanation:

The thermal energy output by the oven is 800 J which is the useful energy that can be utilized for cooking.

The electrical energy input to the oven is 1000 J.

The efficiency of the oven =

(Useful energy output)/(Total energy input to the oven) x 100

=\frac{800}{1000}\times 100= 80\%

Hence, the efficiency of the oven is 80%.

3 0
4 years ago
Review. (c) Assume the dipole is a compass needle-a light bar magnet-with a magnetic moment of magnitude μ . It has moment of in
hammer [34]

The frequency of oscillation is \frac{1}{2\pi }  \sqrt{\frac{\mu B}{I} }.

<h3>What is a magnetic moment?</h3>

The magnetic moment is the magnetism of a magnet or other item that creates a magnetic field, as well as its orientation and strength. Electromagnets, permanent magnets, elementary particles like electrons, different compounds, and a variety of celestial objects are examples of things that have magnetic moments (such as many planets, some moons, stars, etc). The phrase "magnetic moment" typically refers to a system's magnetic dipole moment, which can be represented by an analogous magnetic dipole, which has a magnetic north and south pole that are barely separated from one another. For sufficiently small magnets or at sufficiently wide distances, the magnetic dipole component is adequate. For extended objects, additional terms may be required in addition to the dipole moment, such as the magnetic quadrupole moment.

T = \frac{ Id^{2}\theta }{dt^{2} }

-\mu B\theta=\frac{ Id^{2}\theta }{dt^{2} }

\frac{d^{2}\theta }{dt^{2} } = -(\frac{\mu BI}{\theta} )

By Comparing the above equation with the SHM equation

\frac{d^2 \theta} {dt^{2} } = -\omega^{2} \theta

\omega^{2} =\frac{ \mu B}{I}

Frequency = \frac{\mu}{2\pi }

=\frac{\sqrt{\frac{\mu B}{I} } }{2\pi}

=\frac{1}{2\pi }  \sqrt{\frac{\mu B}{I} }

To learn more about a magnetic moment, visit:

brainly.com/question/17000031

#SPJ4

8 0
1 year ago
Echoic sensory memory is used when a lightning bolt flashes across the sky.
Ahat [919]
If the statement above answers whether the statement is true or false, then the answer is false. It is not true that the echoic sensory memory is used when a lightning bolt flashes across the sky because it does not have that kind of capacity. The echoic sensory memory is the one responsible for the auditory information.
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3 years ago
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