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love history [14]
4 years ago
10

What are the three basic parts of a circuit?

Physics
2 answers:
Nat2105 [25]4 years ago
5 0

Answer: energy source, path, and load

Explanation:

Juliette [100K]4 years ago
3 0

Answer:

1) The wires

2) A component e.g. light

3) A power source

Explanation:

A power source is a basic part of a circuit because if the circuit doesn't have a power source, how will the electrons flow around? . A component is a basic part of a circuit because what's the point of having a circuit without something happening for example a light flashing or a motor turning. Finally, the wires are important because they carry the electrical charge for the component to turn on so if there is no wires there is no electrical flow being carried along

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professor190 [17]
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3 years ago
A flat coil of wire is placed in a uniform magnetic field that is in the y-direction.
Kitty [74]

Answer:

The correct answer is c

Explanation:

Flow is defined by

        Ф =  B . A

bold letters indicate vectors.

The magnetic field is directed to the y axis, The area of ​​the coil is represented by a vector normal to the plane of the coil, so to have a flux

                i.i = j.j = k.k = 1

and the tori scalar products are zero

a) If the coil must be in the xy plane so that its normal vector is in the Z axis, so there is no flux

b) if the coil is in the plane yz the normal veto is in the x axis, so the flux is zero

C) If the coil is in XZ, the normal vector points in the y direction, usually the scalar product is one and there is a flux in this configuration

The correct answer is c

7 0
3 years ago
13.An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane tra
Murrr4er [49]

Answer:

The answer is 3.33m

Explanation:

The acceleration "a" is constant.

Acceleration is the variation of velocity over time,

\frac{dv}{dt} = a.

solving the last equation

\int_{v_0}^v dv = a\int_0^t dt \rightarrow v-v_0 = at,

where v_0=0 because the airplane starts from rest.

Once again, velocity is the variation of distance over time.

\frac{dx}{dt} = at \rightarrow \int_{x_0}^x dx = a\int_0^t t\ dt

then

x- x_0 = \frac{1}{2}at^2

where x_0=0 if we consider  the end of the runway as the initial point (this step is for simplicity but you can let it expressed, it's going to cancel anyway).

If x=1.11\ m at t=1s, then

a = \frac{2x}{t^2} = 2.22\ m/s^2

and the final expression for the distance is

x = 1.11 t^2.

If t = 2s, x = 4.44 m. Which means thad the additional distance is

x(2s) - x(1s) = 4.44 - 1.11 = 3.33\ m

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