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gulaghasi [49]
3 years ago
7

Questions 7-10 please. Please show work it would be preferable. Thank you.

Physics
2 answers:
shutvik [7]3 years ago
8 0

Answer:

7/ 0.3

10/ 0.35N

I don't know about 8 and 9

sorry for that.

STALIN [3.7K]3 years ago
7 0

Answer:

7. 0.333

8. 29,400 N

9. 91,800 m³

10. 0.84 N

Explanation:

7. Friction force = normal force × coefficient of friction

F = Nμ

(50 N) = (150 N) μ

μ = 0.333

8. Buoyant force = weight of displaced fluid.

B = ρVg

B = (1000 kg/m³) (3 m³) (9.8 m/s²)

B = 29,400 N

9. For an object to float, buoyant force = weight of object.

B = W

ρVg = mg

ρV = m

V = m / ρ

V = (91,800,000 kg) / (1000 kg/m³)

V = 91,800 m³

10. Apply Newton's second law:

∑F = ma

F − W = ma

F − mg = ma

F = mg + ma

F = m (g + a)

F = (0.050 kg) (9.8 m/s² + 7 m/s²)

F = 0.84 N

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