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Semenov [28]
3 years ago
15

In which of the following wave types is the particle motion perpendicular to wave motion?

Physics
1 answer:
galben [10]3 years ago
4 0

Answer:

C...................

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find the density, in g/cm3g/cm3 , of a metal cube with a mass of 50.3 gg and an edge length (l)(l) of 2.65 cmcm . for a cube v
Alina [70]

The density of the metal cube is 2.703 g/cm³.

The mass of a metal cube is m =50.3 grams.

The edge length of the metal cube is l = 2.65 cm.

Now, the density (ρ) of a cube can be given as:

ρ = m/(a)³

Where (a)³ is the volume of the cube, m is the mass of the cube, ρ is the density of the cube, and a is the length of one side of the cube.

Since the sides of a cube are equal therefore the value of a is the same for each edge length of the cube.

Now, the density of the metal cube in g/cm³ is:

ρ = m / a³

ρ = m / l³

ρ = 50.3 g / (2.65 cm)³

ρ = 50.3 g / (2.65 cm)(2.65 cm)(2.65 cm)

ρ = 50.3 g / 18.609 cm³

ρ = 2.703 g/cm³

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The origin and development of the universe
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You throw a baseball with a mass of 0.5 kg. The ball leaves your hand with a speed of 35 m/s. Calculate the kinetic energy. (SHO
mixas84 [53]

Answer:

The kinetic energy of the baseball is 306.25 joules.

Explanation:

SInce the baseball can be considered a particle, that is, that effects from geometry can be neglected, the kinetic energy (K), in joules, is entirely translational, whose formula is:

K = \frac{1}{2}\cdot m\cdot v^{2} (1)

Where:

m - Mass, in kilograms.

v - Speed, in meters per second.

If we know that m = 0.5\,kg and v = 35\,\frac{m}{s}, then the kinetic energy of the baseball thrown by the player is:

K = \frac{1}{2}\cdot m \cdot v^{2}

K = 306.25\,J

The kinetic energy of the baseball is 306.25 joules.

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Whitepunk [10]
The answer I believe is c
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