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3 years ago

In which of the following wave types is the particle motion perpendicular to wave motion?

Physics

1 answer:

galben [10]3 years ago

4 0

Answer:

C...................

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Please I need help on this

Alexxandr [17]

Number 4 I think
the atomic mass is 11 because the mass is the sum of protons and neutrons

3 0

3 years ago

I need help in my physics class and show me how it’s done

Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

$A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)$

Where | A | is the magnitude of the vector and $\alpha$ is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle $\alpha$ .

Vector A is in the 4th quadrant

So:

$A_x = 6\\\\A_y = -6.5$

So:

$|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846$

So:

$Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)$

$\alpha$ = -47.28 ° +360° = 313 °

$\alpha$ = 313 °

Option 4.

4 0

3 years ago

The thermal energy of a container of helium gas is halved. what happens to the temperature in kelvin

xxTIMURxx [149]

Thermal energy quantifies the amount of heat present in the body and is calculated through the equation,

H = mcpdT

where H is the heat, m is the mass, cp is the specific heat, and dT is the temperature difference. If all things are constant, and the thermal energy is halved then, dT should also be reduced to half.

5 0

3 years ago

HURRY!!!!

Bingel [31]

I'm not exactly sure but I'm thinking that it's the last one. Sorry if I'm wrong

4 0

3 years ago

Read 2 more answers

You want to slide a 0.39 kg book across a table. If the coefficient of kinetic friction is .21, what force is required to move t

uranmaximum [27]

Find the force that would be required in the absence of friction first, then calculate the force of friction and add them together. This is done because the friction force is going to have to be compensated for. We will need that much more force than we otherwise would to achieve the desired acceleration:

$F_{NoFric}=ma=0.39kg \times0.18 \frac{m}{s^2} =0.0702N$

The friction force will be given by the normal force times the coefficient of friction. Here the normal force is just its weight, mg

$F_{Fric}=0.39kg \times 9.8 \frac{m}{s^2} \times 0.21=0.803N$

Now the total force required is:

0.0702N+0.803N=0.873N

5 0

3 years ago