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4 years ago

If the value of static friction for a couch is 400N, what could be a possible value

Physics

1 answer:

miv72 [106K]4 years ago

3 0

Answer:

kinetic friction may be greater than 400 N or smaller than 400 N

Explanation:

As we know that maximum value of static friction on the rough surface is known as limiting friction and the formula of this limiting friction is known as

$F_s = \mu_s N$

now when object is sliding on the rough surface then the friction force on that surface is known as kinetic friction and the formula of kinetic friction is known as

$F_k = \mu_k N$

now we know that

$\mu_k < \mu_s$

so here value of limiting static friction force is always more than kinetic friction

also we know that

initially when body is at rest then static friction value will lie from 0 N to maximum limiting friction

and hence kinetic friction may be greater than static friction or if the static friction is maximum limiting friction then kinetic friction is smaller than static friction

so kinetic friction may be greater than 400 N or smaller than 400 N

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4vir4ik [10]

his displacements are given as

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$d_2 = 8 km$ North

now we can find the direction of displacement by using the concept

$\theta = tan^{-1}\frac{\deta y}{\delta x}$

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$\theta = 28.1 degree$

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3 years ago

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leonid [27]

Explanation:

KE = 1/2mv^2

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v =

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3 years ago

One of two 25-year-old identical twins begins a trip on a spaceship traveling at 0.8 c while her twin remains on Earth. The twin

borishaifa [10]

Answer:

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Solution:

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The problem can be solved by time dilation equation:

$t = \frac{t_{o}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$ (1)

where,

t = time observed from a different inertial frame

Now, using eqn (1), we get:

$t = \frac{10}{\sqrt{1 - \frac{(0.8c)^{2}}{c^{2}}}}$

t = 16.67 years

The age of the twin on spaceship according to the one on earth = 25+16.67 =41.66 years

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3 years ago

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tigry1 [53]

Answer:

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3 years ago

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Viefleur [7K]

Answer:

111011

Explanation:

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3 years ago