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Dafna1 [17]
2 years ago
15

Sound waves can travel through which mediums?

Physics
1 answer:
aksik [14]2 years ago
5 0

Answer:

B. Solids, liquids, and gases.

Explanation:

I have no explanation.

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Help!
Evgen [1.6K]

Answer:

factory:

-mechanical energy

-nuclear energy

-gravitational energy

Explanation:

8 0
3 years ago
What are groups 1,2 and 3 examples of on the periodic table
pishuonlain [190]
<span>The number of the group identifies the column of the standard periodic table in which the element appears.</span>
Group 1 contains the  alkali metals ( lithium<span> (</span>Li<span>), </span>sodium<span> (</span>Na<span>), </span>potassium<span> (</span>K<span>), </span>rubidium<span> (</span>Rb<span>), </span>caesium<span> (</span>Cs<span>), and </span>francium(Fr).)<span>
Group 2 contains the alkaline earth metals (</span> beryllium<span> (</span>Be),magnesium<span> (</span>Mg<span>), </span>calcium<span> (</span>Ca<span>), </span>strontium<span> (</span>Sr<span>), </span>barium<span> (</span>Ba<span>) and </span>radium<span> (</span>Ra<span>) )
Group 3: </span><span> Scandium (Sc) and yttrium (Y) </span>
4 0
2 years ago
It may seem strange that the selected velocity does not depend on either the mass or the charge of the particle. (For example, w
Charra [1.4K]

Answer:

b) q large and m small

Explanation:

q is large and m is small

We'll express it as :

q > m

As we know the formula:

F = Eq

And we also know that :

F = Bqv

F = \frac{mv^{2} }{r}

Bqv = \frac{mv^{2} }{r}

or Eq = \frac{mv^{2} }{r}

Assume that you want a velocity selector that will allow particles of velocity v⃗  to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v⃗ . To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with q large and m small.

6 0
3 years ago
Is Air <br> Heterogenous<br> Homogenous<br> suspension <br> compound <br> element
Bumek [7]
Air is heterogeneous.
7 0
3 years ago
A 235.0 g metal block absorbs 2.44 × 103 J of heat to raise its temperature by 35 K. What is the specific heat of the metal? Sho
andrew-mc [135]
When an object absorbs an amount of energy equal to Q, its temperature raises by \Delta T following the formula
Q=m C_s \Delta T
where m is the mass of the object and C_s is the specific heat capacity of the material.

In our problem, we have Q=2.44 \cdot 10^3 J, m=235.0 g and \Delta T=35 K, so we can re-arrange the formula and substitute the numbers to find the specific heat capacity of the metal:
C_s =  \frac{Q}{m \Delta T}= \frac{2.44 \cdot 10^3 J}{(235.0 g)(35 K)}=0.297 J g^{-1} K^{-1}
3 0
3 years ago
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