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aliya0001 [1]
3 years ago
9

A block of mass 10kg is moved at a constant speed through a horizontal distance of 4m, by applying a force 50N. How much work ha

s been done when the force is applied in direction?
1- in the same direction of displacement

2- at an angle of 30 with displacement

Physics
1 answer:
algol133 years ago
4 0

Answer:

Explanation:

given that

mass = 10kg

distance = 4m

force = 50N

to calculate the workdone when the force is applied in the same direction of displacement

mathematically,

workdone = force × distance

Workdone = 50 × 4

workdone = 200 joules

2) to calculate the workdone at an angle of 30° with the displacement we apply the formula

workdone = force × distance × cos Ф

workdone = 50 × 4 × cos 30°

workdone = 200 × 0.866

workdone = 173 . 2 joules

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As shown in the diagram, two forces act on an object. The forces have magnitudes F1 = 5.7 N and F2 = 1.9 N. What third force wil
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Second option 6.3 N at 162° counterclockwise from  

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-\frac{F_2}{cos (b)}sin(b)+F_1 = 0\\\\F_1 = \frac{F_2}{cos (b)}sin(b)\\\\F_1 = F_2tan(b)\\\\tan(b) = \frac{F_1}{F_2}\\\\tan(b) = \frac{5.7}{1.9}\\\\tan^{-1}(\frac{5.7}{1.9}) = b\\\\b= 72\°\\\\m = b +90\\\\\m= 162\°

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