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lapo4ka [179]
3 years ago
12

BALANCE the equation

Chemistry
1 answer:
Anna11 [10]3 years ago
8 0

Answer:

1. 4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

2. 6 moles of Cl2

Explanation:

1. The balanced equation for the reaction. This is illustrated below:

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

2. Determination of the number of mole of Cl2 produce when 4 moles of FeCl3 react with 4 moles. To obtain the number of mole of Cl2 produced, we must determine which reactant is the limiting reactant.

This is illustrated below:

From the balanced equation above,

4 moles of FeCl3 reacted with 3 moles of O2.

Since lesser amount of O2 (i.e 3 moles) than what was given (i.e 4 moles) is needed to react completely with 4 moles of FeCl3, therefore FeCl3 is the limiting reactant and O2 is the excess reactant.

Finally, we can obtain the number of mole Cl2 produced from the reaction as follow:

Note: the limiting reactant is used as it will produce the maximum yield of the reaction since all of it is used up in the reaction.

From the balanced equation above,

4 moles of FeCl3 will react to produced 6 moles of Cl2.

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Answer:

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Explanation:

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Two or more elements chemically combined make a?
In-s [12.5K]
Tqo or more elements combine to make a compound.
5 0
3 years ago
What is the mass of 2.47 moles of fluorine (<br> f. atoms? 0.130 g 7.69 g 46.9 g my answer 282 g
mixer [17]

The mass of 2.47 moles of fluorine atom is 46.9 g

calculation

mass of Fluorine= moles x molar mass

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3 0
4 years ago
A 3.25 L solution is prepared by dissolving 285 g of BaBr2 in water. Determine the molarity.
Effectus [21]

Answer:

0.295 mol/L

Explanation:

Given data:

Volume of solution = 3.25 L

Mass of BaBr₂ = 285 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of solute:

Number of moles = mass/ molar mass

Molar mass of BaBr₂ = 297.1 g/mol

Number of moles = 285 g/ 297.1 g/mol

Number of moles= 0.959 mol

Molarity:

M = 0.959 mol / 3.25 L

M = 0.295 mol/L

5 0
3 years ago
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