Answer:
114.44 J
Explanation:
From Hook's Law,
F = ke................. Equation 1
Where F = Force required to stretch the spring, k = spring constant, e = extension.
make k the subject of the equation
k = F/e.............. Equation 2
Given: F = 10 lb = (10×4.45) N = 44.5 N, e = 4 in = (4×0.254) = 1.016 m.
Substitute into equation 2
k = 44.5/1.016
k = 43.799 N/m
Work done in stretching the 9 in beyond its natural length
W = 1/2ke²................. Equation 3
Given: e = 9 in = (9×0.254) = 2.286 m, k = 43.799 N/m
Substitute into equation 3
W = 1/2×43.799×2.286²
W = 114.44 J
First, we have a change in the velocity from 85 to 164 m/s in 10 sec.
Then, we calculate the <u>acceleration </u>as:
Hence we need to calculate the velocity of the space vehicle at t = 2 sec using the first equation of motion:
Then, using the second equation of motion to calculate the distance:
The correct answer is 195.6 N
Explanation:
Different from the mass (total of matter) the weight is affected by gravity. Due to this, the weight changes according to the location of a body in the universe as gravity is not the same in all planets or celestial bodies. Moreover, this factor is measured in Newtons and it can be calculated using this simple formula W (Weight) = m (mass) x g (force of gravity). Now, leps calculate the weigh of someone whose mass is 120 kg and it is located on the moon:
F = 120 kg x 1.63 m/s2
F= 195.6 N
Answer:
thanks for da 5points hoi
Explanation: thanks dawg
Answer:
(a)
(b)
Explanation:
mass, m = 2.3 kg
vx = 40 m/s
vy = 75 m/s
(a) Angular momentum is given by
Where, p is the linear momentum and r is the position vector about which the angular momentum is calculated.
Here,
So, the angular momentum
(b) Here,