Consider a beam of electrons in a vacuum,passing through a very narrow slit of width 2.00 \;\mu{\rm m} . The electrons then head
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Answer:
Option A
Solution:
As per the question:
The distance covered by the woman in the North direction, d = 3000 m
Time taken to travel in North direction, t = 25.0 min = 1500 s
Velocity of woman in the south direction, v = 2.00 m/s
Time taken in the south direction, t' = 60.0 min = 3600 s
Now,
The distance covered in the south direction, d' = vt' =
Now, the total displacement is given by:
D = d' - d = 7200 - 3000 = 4200 m in South
(a) Average velocity of the woman in the whole journey is given by:
≈ 0.824 m/s South
Answer:
54
Explanation:
where initial velocity
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