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KiRa [710]
3 years ago
5

A baseball pitcher loosens up his pitching arm. He tosses a 0.20-kg ball using only the rotation of his forearm, 0.28 m in lengt

h, to accelerate the ball. What is the moment of inertia of the ball alone as it moves in a circular arc with a radius of 0.28 m?
Physics
1 answer:
aev [14]3 years ago
7 0

Answer:

Moment of Inertia, I = 0.016 kgm²

Explanation:

Mass of the ball, m = 0.20 kg

Length of the pitcher's arm, l = 0.28

Radius of the circular arc, r = 0.28 m

Moment of Inertia is given by the formula:

I = mr²

I = 0.20 * 0.28²

I = 0.20 * 0.0784

I = 0.01568

I = 0.016 kgm²

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Lorico [155]

Answer:

D. 196 J

Explanation:

PE=mgh=10×9.8×2=196J

6 0
3 years ago
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PART 2 OF ENERGY AND FORCES UNIT TEST
katrin2010 [14]

Answer:

1. at least two charged interacting parts

2. from the electric fields of charged subatomic particles

3 an arrow released from the bow

4Electrical fields of charged particles interact, bonding those with opposite charges.

5 the interaction of the electric fields of protons and electrons

6 The energy stored in the system increases.

7 Kinetic energy increases because the magnets move in the direction of the field.

8 Iron pieces accelerate toward the magnet, and the energy stored in the system decreases.

9  

The energy stored in the field decreases because the magnet moves in the direction of the field.

10 The energy stored increases and then decreases.

11 The wire was not connected to the source.

12  The electromagnet will become more powerful.

the rest are written, hope this helps (:

4 0
3 years ago
You are moving a wagon with a friend's help you push on the left side of the wagon with 25 of force while your friend pulls from
Pavel [41]

Answer:

10N to the left side towards you

Explanation:

The net force is the resultant force that acts on a body.

Force is a push or pull on a body.    

 Push to left side  = 25N

 Pull to the right  = 15N

Net force  = Push to left side   -  Pull to the right  = 25N  - 15N

 Net force  = 10N to the left side towards you

The net force is therefore 10N to the left side towards you

5 0
3 years ago
How much kinetic energy does a system containing 3 moles of an ideal gas at 300 K possess? What is the heat capacity at constant
ElenaW [278]

Answer:

1. K.E = 11.2239 kJ ≈ 11.224 kJ

2. C_{V} = 37.413 JK^{- 1}

3. Q = 10.7749 kJ

Solution:

Now, the kinetic energy of an ideal gas per mole is given by:

K.E = \frac{3}{2}mRT

where

m = no. of moles = 3

R = Rydberg's constant = 8.314 J/mol.K

Temperature, T = 300 K

Therefore,

K.E = \frac{3}{2}\times 3\times 8.314\times 300

K.E = 11223.9 J = 11.2239 kJ ≈ 11.224 kJ

Now,

The heat capacity at constant volume is:

C_{V} = \frac{3}{2}mR

C_{V} = \frac{3}{2}\times 3\times 8.314 = 37.413 JK^{- 1}

Now,

Required heat transfer to raise the temperature by 15^{\circ} is:

Q = C_{V}\Delta T

\Delta T = 15^{\circ} = 273 + 15 = 288 K

Q = 37.413\times 288 = 10774.9 J = 10.7749 kJ

8 0
3 years ago
A 2.00-kg ball is moving at 2.20 m/s toward the right. It collides elastically with a 4.00-kg ball that is initially at rest. 1)
loris [4]
Elastic collision is when kinetic energy before = kinetic energy after

Ek= 1/2mv^2

total before
Ek=1/2(2)(2.2^2) = 4.84 J

total after
Ek= 1/2(2+4)(v^2) = 3v^2

Before = after
4.84=3v^2 | divide by 3
121/75 = v^2 | square root both sides
v=1.27 m/s
7 0
3 years ago
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