The fraction of radioisotope left after 1 day is 
, with the half-life expressed in days
Explanation:
The question is incomplete: however, we can still answer as follows.
The mass of a radioactive sample after a time t is given by the equation:
where:
is the mass of the radioactive sample at t = 0
is the half-life of the sample
This means that the mass of the sample halves after one half-life.
We can rewrite the equation as
And the term on the left represents the fraction of the radioisotope left after a certain time t.
Therefore, after t = 1 days, the fraction of radioisotope left in the body is
where the half-life must be expressed in days in order to match the units.
Learn more about radioactive decay:
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Answer:
I would guess they'd probably be in an area they feel is habitatible.
Answer:
<h2>300 J</h2>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 2 × 10 × 15
We have the final answer as
<h3>300 J</h3>
Hope this helps you
Answer:
The displacement of the air drop after 3 second is 18.27 m.
Explanation:
Mass of the rain drop = m = 
Weight of the rain drop = W
Duration of time = t = 3 seconds
Drag force on rain drop = 
Motion of the rain drop:
Net force on the rain drop , F= W - D
v = 12.18 m/s
Initial velocity of the rain drop = u = 0 (since, it is starting from rest)
v=u+at (First equation of motion)
(second equation of motion)
s = 18.27 m
The displacement of the air drop after 3 second is 18.27 m.
