Answer:
<h2>127.57 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have

We have the final answer as
<h3>127.57 moles</h3>
Hope this helps you
Onization energy is the energy required to lose an electron and form an ion. The stronger is the attraction of the atom and the electron the higher the ionization energy, and the weaker is the attraction of the atom and the electron the higher the ionization energy. This leads to a clear trend in the periodic table. Given that the larger the atom the weaker the attraction of the atom to the valence electrons, the easier they will be released, and the lower the ionization energy. This is, as you go downward in a group, the ionization energy decreases. So, the element at the top of the group will exhibit the largest ionization energy. <span>Therefore, the answer is that of the four elements of group 7A, fluorine will have the largest first ionization energy.</span>
PV = nRT —> P = nRT/V
n = 0.250 moles of gas
R = 0.08206 L atm / mol K
T = 18 + 273 = 291 K
V = 7.50 L
P = (0.250)(0.08206)(291)/(7.50) = 7.96 atm
Hey There!
To solve this question remember that 1 mole of ammonia is equal to 17G of ammonia.
Using that, we first multiply 17 by 7 = 24
Then we multiply 7 by .27 = 1.89
Finally, taking those and adding them together gives you the answer...
<u>25.89 grams :)</u>
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<u>Have a great day, I hope I helped.</u>
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<u>+ Brainliest & Five stars are always appreciated </u>