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lianna [129]
2 years ago
14

When paper turns yellow-brown upon exposure to sunlight, what type of change is likely taking place?

Chemistry
1 answer:
sveticcg [70]2 years ago
8 0

the answer to this is chemical change

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The lattice structure in a metal is _____ than the lattice structure of an ionic compound.
Salsk061 [2.6K]
<span>The lattice structure in a metal is weaker than the lattice structure of an ionic compound. This is because the metals have free electrons which can freely move around while ionic compounds are strongly bonded. Hope this answers the question.</span>
8 0
3 years ago
Please help me for question 1 and 2
likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
3 years ago
Which of the following is not equal to 120 centimeters?
tia_tia [17]
<h3>Answer:</h3>

0.012 dekameters (dkm)

<h3>Explanation:</h3>

<u>We are given;</u>

  • 120 centimeters( cm).

Required to identify the measurements that is not equivalent to 120 cm.

  • Centimeters are units that are used to measure length together with other units such as kilometers(km), meters (m), millimeters (mm), dekameters (dkm), etc.
  • These units can be inter-converted to one another using suitable conversion factors.
  • To do this, we are going to have a table showing the suitable conversion factor from one unit to another.

Kilometer (km)

10

Decimeter (Dm)

10

Hectometer (Hm)\

10

Meter (m)

10

Dekameter (dkm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore;

To convert cm to km

Conversion factor is 10^5 cm/km

Thus;

120 cm = 120 cm ÷ 10^5 cm/km

            = 0.0012 km

To convert cm to dkm

Conversion factor is 10 cm/dkm

Therefore,

120 cm = 120 cm ÷ 10 cm/dkm

            = 12 dkm

To convert cm to m

The suitable conversion factor is 10^2 cm/m

Thus,

120 cm = 120 cm ÷ 10^2 cm/m

           = 1.2 m

To convert cm to mm

Suitable conversion factor is 10 mm/cm

Therefore;

120 cm = 120 cm × 10 mm/cm

            = 1200 mm

Therefore, the measurement that is not equal to 120 cm is 0.012 dkm

4 0
3 years ago
Thallium has two stable isotopes, 203tl and 205tl. knowing that the atomic weight of thallium is 204.4, which isotope is the mor
Elza [17]
You have to figure out a way to write the two unknown abundances in terms of one variable.

The total abundance is 1 (or 100%). So if you say the abundance for the first one is X then the abundance for the second one has to be 1-X (where X is the decimal of the percentage so say 0.8 for 80%).

203(X) + 205(1-X) = 204.4

Then you just solve for X to get the percentage for TI-203.
And then solve for 1-X to get the percentage for TI-205.

After that the higher percentage would be the most abundant.

203x + 205 - 205x = 204.4
-2x + 205 = 204.4
-2x = -0.6

x = 0.3
1-x = 0.7

Then the TI-205 would have the highest percentage and would be the most abundant.
7 0
3 years ago
Nitrogen and water react to form nitrogen monoxide and hydrogen, like this: N2(g) + 2H2O(g) → 2NO(g) +2H2(g) Also, a chemist fin
Thepotemich [5.8K]

Answer:

Kc for this reaction is 0.43

Explanation:

This is the equilibrium:

N₂(g) + 2H₂O(g) → 2NO(g) +2H₂(g)

And we have all the concentration at equilibrium:

N₂: 0.25M

H₂ : 1.3M

NO: 0.33M

H₂: 1.2M

They are ok, because they are in MOLARITY. (mol/L)

Let's make the expression for Kc

Kc = ( [NO]² . [H₂]² ) / ([N₂] . [H₂O]²)

Kc = (0.33² . 1.2²) / (0.25 . 1.2²)

Kc = 0.4356

In two significant digits. 0.43

8 0
3 years ago
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