That would be c. :) :) :)
Answer:
Explanation:
Let the intensity of unpolarised light be I₀ . After passing through the first polarising filter , the intensity is I₀ / 2 .
After second filter , the intensity will be I₀ / 2 x cos²45 = I₀ / 4
After third filter , the intensity will be I₀ / 4 x cos²45 = I₀ / 8 .
So,
1 / 8 the of initial light passes through the last filter .
Answer:
N= 238 turns
Explanation:
The induced Emf that goes through a solenoid can be calculated using the below formula;
Where ξ=induced Emf
L= self inductance
I= current
ξ= L|dⁱ/dt|
Making L which is the self inductance subject of formula we have
L=ξ/[|dⁱ|*|dt|]
The current here is changing at the rate of
.0260 A/s
L=NΦB/i
N=ξ/Φ|di|*|dt|
Magnitude of the induced Emf given= 12.6mV then if we convert to volt we have 12.6×10⁻³ V
The current I = 1.40A
Magnitude flux through the flux=/0.00285 Wb
Then if we substitute all this Value to equation above we have
N=(12.6×10⁻³ V×1.40A)/(0.00285 Wb×0.0260 A/s)
N=238turn
Therefore, there are 238turns in the solenoid
As we know that here gun + bullet system is isolated from all other external force system
so here the momentum of system is always conserved
so we will say

here we know that




now we will have

by solving above equation we will have
