Your answer is cumulonimbus clouds
Answer: 5.30m
Explanation:
depth of pool = 3.2 m
i = 67.75°
Using snell's law, we have,
n₁ × sin(i) = n₂ × 2 × sin(r)
n₁ = 1, n₂ =1.33, r= 44.09°
Hence,
Distance of Google from edge if pool is:
2.2 + d×tan(r) = 2.2 + (3.2 × tan(44.09°) =5.30m
Answer:
I think the acceleration is 12m/s
Data:

n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>

Wire 2 → 2º Harmonic → n = 2







Wire 1 → 1º Harmonic or Fundamental rope → n = 1



If, We have:
V = 42L
Soon:



Answer:
<span>The fundamental frequency of the string:
</span>
21 Hz
Answer:
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Explanation:
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