<u>Answer:</u> The mass of 97 % of NaOH solution required is 114.33 g
<u>Explanation:</u>
To calculate mass of a substance, we use the equation:
We are given:
Density of 10 % solution = 1.109 g/mL
Volume of 10% solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
The mass of 10 % solution is 1109 g.
To calculate the mass of concentrated solution, we use the equation:
where,
are the concentration and mass of concentrated solution.
are the concentration and mass of diluted solution.
We are given:
Putting values in above equation, we get:
Hence, the mass of 97 % of NaOH solution required is 114.33 g
The element to which this atom belongs is a p-block main-group element.
What is general electronic configuration?
Electronic configuration or general electron configuration or electronic structure of atoms or ions is the arrangement of orbital energy levels for s, p, d, and f-block elements of the periodic table.
Which group are p-block elements in the periodic table write the general electronic configuration of a p-block element?
Groups 13, 14, 15, 16, and 17 elements comprise the p-block elements. The general configuration of p-block elements is ns2np(1−6).
What is the general configuration of p- block elments?
The general electronic configuration of p-block elements is ns2np1-6 (Except Helium). The number of electrons in the p-block element's penultimate shell is either 2 or 8 or 18.
Therefore, the element belongs to the p-block.
To know more about p-block elements:
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Answer:
CO(g) + H₂O(g) <=> CO₂(g) + H₂(g), (volume is decreased) .. No effect.
PCl₃(g) + Cl₂(g) <=> PCl₅(g)
, (volume is increased) .. Shift left.
CaCO₃(s) <=> CaO(s) + CO₂(g)
, (volume is increased) .. Shift right.
Explanation:
<em>Le Châtelier's principle</em><em> states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
<em />
<em>CO(g) + H₂O(g) <=> CO₂(g) + H₂(g) (volume is decreased)</em>
- When volume is decreased, the pressure will increase:
- When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 2.0 moles of gases and the products side (right) has 2.0 moles of gases.
So, decreasing the volume will have no effect on the reaction.
<em>PCl₃(g) + Cl₂(g) <=> PCl₅(g)
, (volume is increased)</em>
- When volume is increased, the pressure will decrease:
- When there is an decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 2.0 moles of gases and the products side (right) has 1.0 mole of gases.
- So, decreasing the pressure will shift the reaction to the side with more moles of gas (left side).
so, increasing the volume will shift the reaction left.
<em>CaCO₃(s) <=> CaO(s) + CO₂(g)
, (volume is increased)</em>
- When volume is increased, the pressure will decrease:
- When there is an decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 0 moles of gases and the products side (right) has 1.0 mole of gases.
- So, decreasing the pressure will shift the reaction to the side with more moles of gas (right side).
so, increasing the volume will shift the reaction right.
Explanation:
protons and neutrons.....
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