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Taya2010 [7]
3 years ago
8

Dinitrogen tetraoxide and nitrogen dioxide are two gases that exist in equilibrium at a range of temperatures. NO2 is a reddish

brown gas while N2O4 is colorless.... At High Temperature the red color is strong. ...... At Low Temperature the gas has less color. ...If we represent the equilibrium as:... 2 NO2(g) Doublearrow.GIFN2O4(g) We can conclude that:1. This reaction is:A. ExothermicB. EndothermicC. NeutralD. More information is needed to answer this question.2. When the temperature is decreased the equilibrium constant, K:A. IncreasesB. DecreasesC. Remains the sameD. More information is needed to answer this question.3. When the temperature is decreased the equilibrium concentration of NO2:A. IncreasesB. DecreasesC. Remains the sameD. More information is needed to answer this question.
Chemistry
1 answer:
Vilka [71]3 years ago
6 0

Answer:

1-C

2-A

3-B

Explanation:

K=[N204]/[NO2]

In the first question the reaction is at equilibrium. When the temperature is decreased, more N2O4 if formed and K increases. When the temperature is increased, more NO2 is formed and K decreases.

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the half life of I -137 is 8.07 days. if 24 grams are left after 40.35 days, how many grams were in the original sample?
Ray Of Light [21]

Answer:

768g

Explanation:

We can use to formula N(A) = N_0(\frac{1}{2})^\frac{t}{t_{1/2}} . Here, N(A) is the final amount. N0 is the initial amount. t is the time elapsed, and t_{1/2} is the half life. Plugging in, we get the answer above.

4 0
3 years ago
Suppose that a fictitious element, x, has two isotopes: 59x (59.015 amu) and 62x (62.011 amu). the lighter isotope has an abunda
professor190 [17]

The atomic mass of the element would simply be equal to the sum of the weighted average of each isotope, that is:

atomic mass = 59.015 amu * 0.717 + 62.011 amu * (1 – 0.717)

<span>atomic mass = 59.863 amu</span>

4 0
3 years ago
What is the ph of a solution that results from mixing 25 ml of 0.15 M hcl to 25 ml of 0.52 m nh3?
BartSMP [9]

Answer:

7.00

Explanation:

When the solutions are mixed, the HCl dissociates to form the ions H+ and Cl-. The ion H+ will react with the NH3 to form NH4+. The stoichiometry for this is 1 mol of HCl to 1 mol of H+ to 1 mol of Cl-, and 1 mol of H+ to 1 mol of NH3 to 1 mol of NH4+.

First, let's find the number of moles of each one of them, multiplying the concentration by the volume:

nH+ = 0.15 M * 25 mL = 3.75 mmol

nNH3 = 0.52 M * 25 mL = 13 mmol

So, all the H+ is consumed, and the neutralization is completed, thus pH will be the pH of the solvent (water), pH = 7.00.

5 0
3 years ago
Number 14? Please :)
ASHA 777 [7]
Evaporated is the answer
4 0
2 years ago
At a given temperature, the elementary reaction A − ⇀ ↽ − B , A↽−−⇀B, in the forward direction, is first order in A A with a rat
Svetllana [295]

Answer:

The equilibrium constant for the reversible reaction = 0.0164

Explanation:

At equilibrium the rate of forward reaction is equal to the rate of backwards reaction.

The reaction is given as

A ⇌ B

Rate of forward reaction is first order in [A] and the rate of backward reaction is also first order in [B]

The rate of forward reaction = |r₁| = k₁ [A]

The rate of backward reaction = |r₂| = k₂ [B]

(Taking only the magnitudes)

where k₁ and k₂ are the forward and backward rate constants respectively.

k₁ = 0.010 s⁻¹

k₂ = 0.0610 s⁻¹

|r₁| = 0.010 [A]

|r₂| = 0.016 [B]

At equilibrium, the rate of forward and backward reactions are equal

|r₁| = |r₂|

k₁ [A] = k₂ [B] (eqn 1)

Note that equilibrium constant, K, is given as

K = [B]/[A]

So, from eqn 1

k₁ [A] = k₂ [B]

[B]/[A] = (k₁/k₂) = (0.01/0.0610) = 0.0163934426 = 0.0164

K = [B]/[A] = (k₁/k₂) = 0.0164

Hope this Helps!!!

5 0
3 years ago
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