Answer:
Explanation:
Hello there!
In this case, since the titration of bases when using monoprotic acids like KHP, occurs in a 1:1 mole ratio, it is possible to use the following equation, because at the endpoint the moles of the KHP and KOH get equal:
In such a way, we first calculate the moles of KOH given the mass and molar mass of KHP:
Next, since we have the volume of KOH, we first take it to liters (0.04571 L) to that we obtain the following concentration:
Regards!
<u>Answer:</u> The mass of nickel that was originally heated is 28.4 grams.
<u>Explanation:</u>
When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.
The equation used to calculate heat released or absorbed follows:
......(1)
where,
q = heat absorbed or released
= mass of nickel = ?
= mass of water = 150.0 g
= final temperature = 25.0°C
= initial temperature of nickel = 99.8°C
= initial temperature of water = 23.5°C
= specific heat of nickel = 0.444 J/g°C
= specific heat of water= 4.186 J/g°C
Putting values in equation 1, we get:
Hence, the mass of nickel that was originally heated is 28.4 grams.