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Delvig [45]
3 years ago
9

Examples of exponential decay in the real-world.

Chemistry
1 answer:
RUDIKE [14]3 years ago
4 0
The decay of dead things and soil
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Calculate the molar mass of each of the following:
Allushta [10]

Explanation:

Molar mass

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

(a) S₈

Molar mass of of the atoms are -

sulfur, S = 32 g/mol.

Molar mass of  S₈ = 8 * 32 g/mol.  = 256 g/mol.

(b) C₂H₁₂

Molar mass of of the atoms are -

Hydrogen , H = 1 g/mol

Carbon , C = 12 g/mol

Molar mass of C₂H₁₂ = ( 2 * 12 ) + (12 * 1 ) = 36 g /mol

(c) Sc₂(SO₄)₃

Molar mass of of the atoms are -

sulfur, S = 32 g/mol.

oxygen , O = 16 g/mol.

scandium , Sc = 45 g/mol.

Molar mass of Sc₂(SO₄)₃ = (2 * 45 ) + ( 3 *32 ) + ( 12 * 16 ) = 378 g /mol  

(d) CH₃COCH₃ (acetone)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol

oxygen , O = 16 g/mol.

Hydrogen , H = 1 g/mol

Molar mass of CH₃COCH₃ (acetone) = (3 * 12 ) + ( 1 * 16 ) + ( 6 * 1 ) = 58g/mol

(e) C₆H₁₂O₆ (glucose)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol

oxygen , O = 16 g/mol.

Hydrogen , H = 1 g/mol

Molar mass of C₆H₁₂O₆ (glucose) = ( 6 * 12 ) + ( 12 * 1 ) + ( 6 * 16 ) = 108g/mol.

6 0
3 years ago
Calculate the mass of bromine in 50.0 g of potassium bromide
Elodia [21]

Answer:

6 Percent Composition. 1. Molar Mass of KBr K = 1(39.10) = 39.10 Br =1(79.90) =79.90 MM = 119.0 79.90 g        119.0 g = 0.6714 3. 0.6714 x 50.0g = 33.6 g Br 2.

4 0
2 years ago
2/10
emmainna [20.7K]

Answer:

pH=2.34

Explanation:

HBr  -> H  + Br

The dissociation it's complete, for that reason the concentration of the products is the same of HBr

[H+]=[Br-]=0.00234 M

pH= - log (0.00234)=2.34

6 0
3 years ago
Is this right, I feel like its wrong
hjlf

It is correct, next time re-check your answer and don't second guess yourself. ;3

7 0
3 years ago
Perform the following metric conversions: Please explain bc I really dont get it at ALL !!!!
makkiz [27]

Answer:

0.2007 nm

3.57 cm

0.01478 g

8280000 pg

Explanation:

1)200.7 pm

1 picometer is equal to 0.001 nanometer.

1 nm = 1000 pm

200.7 pm× 1 nm / 1000 pm  = 0.2007 nm

2)0.000357 hm

1 hectometer is equal to 10,000 centimeter.

1 hc = 10,000 cm

0.000357 hc× 10,000 cm / 1 hc = 3.57 cm

3) 14.78 mg

1 gram is equal to 1000 milligram.

1 g = 1000 mg

14.78 mg × 1 g/1000 mg = 0.01478 g

4)8.280 µg

1 microgram is equal to 10⁶ picogram.

1 µg = 1000000 pg

8.280 µg× 10⁶ pg/ 1µg = 8.280×10⁶ pg or 8280000 pg

7 0
3 years ago
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